By the end of this chapter you'll be able to…

  • 1Identify AP from sequences
  • 2Find nth term using aₙ = a + (n−1)d
  • 3Calculate sum of n terms
  • 4Solve word problems
  • 5Use AP properties (three or five terms)
💡
Why this chapter matters
AP appears in finance (EMI, increments), physics, daily patterns. Foundation for Class 11 GP and infinite series.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Arithmetic Progressions — Class 10 Mathematics

"Numbers in sequence — the rhythm of mathematics."

1. About the Chapter

Arithmetic Progression (AP) is a sequence where the DIFFERENCE between consecutive terms is constant. Used in:

  • Loans and EMIs
  • Salary increments
  • Saving plans
  • Physics (uniform motion)
  • Engineering and architecture

Definition

A sequence a₁, a₂, a₃, ... is an AP if aₙ − aₙ₋₁ = d (constant) for all n ≥ 2.

Components

  • a (first term): a₁ or just 'a'
  • d (common difference): aₙ − aₙ₋₁
  • n (number of terms)

Examples

  • 2, 5, 8, 11, 14, ... (a = 2, d = 3)
  • 10, 7, 4, 1, −2, ... (a = 10, d = −3)
  • 100, 100, 100, ... (a = 100, d = 0)

2. The nth Term

Formula

aₙ = a + (n−1)d

where:

  • aₙ = nth term
  • a = first term
  • d = common difference
  • n = position

Derivation

  • a₁ = a
  • a₂ = a + d
  • a₃ = a + 2d
  • a₄ = a + 3d
  • ...
  • aₙ = a + (n−1)d

Examples

Example 1: Find 20th term of 5, 8, 11, ...

  • a = 5, d = 3
  • a₂₀ = 5 + (20−1)(3) = 5 + 57 = 62

Example 2: Which term of 3, 8, 13, ... is 78?

  • a = 3, d = 5
  • aₙ = 3 + (n−1)(5) = 78
  • 5n − 2 = 78 → n = 16

3. Sum of n Terms (Sₙ)

Formula 1 (when a, d, n known)

Sₙ = (n/2) [2a + (n−1)d]

Formula 2 (when a, l, n known, where l is the last term)

Sₙ = (n/2) (a + l)

Sum of First n Natural Numbers

1 + 2 + 3 + ... + n = n(n+1)/2 (where a = 1, d = 1, l = n)

Sum of First n Odd Numbers

1 + 3 + 5 + ... + (2n−1) = (a = 1, d = 2)

Sum of First n Even Numbers

2 + 4 + 6 + ... + 2n = n(n+1)


4. Properties of AP

Property 1

If you add (or subtract) same number to each term, it's still an AP with same d.

Property 2

If you multiply each term by k, it's still an AP with new d' = kd.

Property 3

Three terms in AP: (a−d), a, (a+d)

Property 4

Five terms in AP: (a−2d), (a−d), a, (a+d), (a+2d)

These properties simplify problem-solving.


5. Worked Examples

Example 1: Identify AP

Is 7, 13, 19, 25, ... an AP?

  • Differences: 6, 6, 6 — constant
  • YES, AP with a = 7, d = 6

Example 2: Find Specific Term

The 4th term of an AP is 14, 12th term is 38. Find first term and common difference.

  • a + 3d = 14 ... (i)
  • a + 11d = 38 ... (ii)
  • Subtract: 8d = 24 → d = 3
  • a = 14 − 9 = 5
  • AP: 5, 8, 11, 14, ...

Example 3: Sum

Find sum: 2 + 5 + 8 + ... + 32

  • a = 2, d = 3, l = 32
  • 32 = 2 + (n−1)(3) → n = 11
  • S = (11/2)(2 + 32) = (11/2)(34) = 187

Example 4: Word Problem

A man saves ₹100 in first year, ₹200 in second, ₹300 in third, and so on. How much in 10 years?

  • a = 100, d = 100, n = 10
  • S = (10/2)[2(100) + 9(100)] = 5(1100) = ₹5500

Example 5: Three Terms in AP

Three numbers are in AP. Their sum = 24, product = 440. Find them.

  • Let numbers be (a−d), a, (a+d)
  • Sum: 3a = 24 → a = 8
  • Product: (8−d)(8)(8+d) = 440
  • 8(64 − d²) = 440 → 64 − d² = 55 → d² = 9 → d = ±3
  • Numbers: 5, 8, 11 (or 11, 8, 5)

6. Common Mistakes

  1. Confusing d with first term

    • d is COMMON DIFFERENCE, not a₁.
  2. Wrong formula for nth term

    • aₙ = a + (n−1)d, not a + nd.
  3. Sum formula confusion

    • Sₙ = (n/2)[2a + (n−1)d] = (n/2)(a + l)
  4. Negative d in increasing sequence

    • If terms increase, d > 0; decrease, d < 0.
  5. Not identifying AP

    • Check differences are CONSTANT. Otherwise not AP.

7. Real-World Applications

Personal Finance

  • Salary increment: ₹3000/year increment is AP
  • EMI patterns: some loan structures use AP
  • Recurring deposits: monthly deposits

Engineering

  • Construction layers
  • Bridge cable lengths
  • Heat treatment temperatures

Sports/Statistics

  • Score progressions
  • Race timings

Physics

  • Uniform velocity: positions form AP
  • Falling object: positions every second form AP

8. Indian Heritage

Indian mathematicians worked on series:

  • Aryabhata (~5th century): sum formulas
  • Mahavira (~9th century): comprehensive treatment
  • Bhaskara II (12th century): general formulas
  • Madhava (14th century): infinite series

Gauss's 'add pairs from ends' trick is essentially what Indians had been using.


9. Conclusion

Arithmetic Progressions are SIMPLE but POWERFUL:

  • Recognise patterns
  • Find specific terms
  • Calculate sums efficiently
  • Apply to real life (finance, physics, engineering)

In Class 11, you'll learn GEOMETRIC PROGRESSIONS (multiply by constant ratio) and INFINITE SERIES. This chapter is the foundation.

Practice 20+ problems. Master formulas. Apply to word problems.

AP: The mathematical music of regularly spaced numbers.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

nth term
aₙ = a + (n−1)d
Sum formula 1
Sₙ = (n/2)[2a + (n−1)d]
When a, d, n given
Sum formula 2
Sₙ = (n/2)(a + l)
When a, l, n given
Sum of 1 to n
n(n+1)/2
Sum of first n odd
Three terms in AP
(a−d), a, (a+d)
⚠️

Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
nth term wrong formula
aₙ = a + (n−1)d. The (n−1) is key, not n.
WATCH OUT
Confusing terms position
Position n starts from 1. a₁ is first term, a₂ is second, etc.
WATCH OUT
Negative d ignored
AP can decrease (d < 0). Always check sign of d.

NCERT exercises (with solutions)

Every NCERT exercise from this chapter — what it covers and how many questions to expect.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· nth
Find 15th term of AP: 2, 5, 8, ...
Show solution
✦ Answer: a = 2, d = 3. a₁₅ = 2 + 14(3) = 2 + 42 = 44.
Q2EASY· Sum
Find sum of first 10 terms of AP: 3, 7, 11, ...
Show solution
✦ Answer: a = 3, d = 4. S₁₀ = (10/2)[2(3) + 9(4)] = 5[6 + 36] = 5(42) = 210.
Q3MEDIUM· Find AP
In an AP, 5th term is 16 and 9th term is 28. Find the AP.
Show solution
Step 1 — Set equations. a₅ = a + 4d = 16 a₉ = a + 8d = 28 Step 2 — Subtract. 4d = 12 → d = 3 Step 3 — Find a. a + 12 = 16 → a = 4 Step 4 — AP. 4, 7, 10, 13, 16, 19, 22, 25, 28, ... ✦ Answer: AP is 4, 7, 10, 13, ... (a = 4, d = 3).
Q4HARD· Word problem
Find the sum of all multiples of 7 lying between 100 and 500.
Show solution
Step 1 — Find first and last terms. First multiple of 7 after 100: 105 (since 14×7 = 98 < 100 and 15×7 = 105) Last multiple of 7 before 500: 497 (since 71×7 = 497 and 72×7 = 504) Step 2 — Identify AP. a = 105, d = 7, l = 497 Step 3 — Find number of terms. l = a + (n−1)d 497 = 105 + (n−1)(7) 392 = 7(n−1) n − 1 = 56 → n = 57 Step 4 — Find sum. S = (n/2)(a + l) = (57/2)(105 + 497) = (57/2)(602) = 57 × 301 = 17,157 Step 5 — Verify. Average of 105 and 497 = 301; 57 terms × 301 = 17,157 ✓ ✦ Answer: Sum of all multiples of 7 between 100 and 500 = 17,157.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • AP: sequence with constant difference d
  • nth term: aₙ = a + (n−1)d
  • Sum: Sₙ = (n/2)[2a + (n−1)d] = (n/2)(a + l)
  • Sum of 1 to n: n(n+1)/2
  • Sum of n odd: n²
  • Three terms in AP: (a−d), a, (a+d)
  • Common Indian heritage: Aryabhata, Bhaskara II

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 8-10 marks per chapter

Question typeMarks eachTypical countWhat it tests
MCQ12Identify AP, formulas
Short Answer2-32nth term, sum
Long Answer51Word problems, find unknown AP
Prep strategy
  • Memorise nth term and sum formulas
  • Practice 15+ problems
  • Word problems on saving, salary, scores
  • Master finding common difference

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Salary increments

Annual increment of fixed amount forms an AP.

EMI loans

Equal monthly instalments use AP-like structures.

Savings plans

Recurring deposits accumulate in AP pattern (with constant deposit).

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Write formula at start
  2. Find a and d
  3. Apply correct formula

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Geometric Progressions
  • Infinite series
  • Telescoping series
  • Indian Madhava's series for π

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 10 BoardVery High
Maths OlympiadHigh
JEE FoundationVery High

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

AP (Arithmetic Progression): constant DIFFERENCE (add same number each time). GP (Geometric Progression): constant RATIO (multiply by same number each time). 2, 5, 8, 11 is AP (+3). 2, 6, 18, 54 is GP (×3). You'll study GP in Class 11.
Verified by the tuition.in editorial team
Last reviewed on 20 May 2026. Written and reviewed by subject-matter experts — read about our process.
Editorial process →
Header Logo