By the end of this chapter you'll be able to…

  • 1Define magnetic flux and state Faraday's laws
  • 2Apply Lenz's law to find the direction of induced current
  • 3Calculate self-inductance and energy stored in an inductor
  • 4Compute mutual inductance between coils
  • 5Explain the AC generator and eddy currents
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Why this chapter matters
A changing magnetic field creates electricity -- the principle behind generators, transformers, and induction cooktops. Faraday's and Lenz's laws, self- and mutual inductance, and the AC generator power the modern electrical world.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Electromagnetic Induction

'If you can change a magnetic field, you can create electricity. This is INDUCTION — and it powers the modern world.'

1. Chapter Overview

Electromagnetic induction is the phenomenon of producing an INDUCED EMF (and current) when the magnetic flux through a circuit CHANGES. Topics include: FARADAY'S LAWS of electromagnetic induction, LENZ'S LAW (determining the direction of induced current), SELF-INDUCTANCE (the property of a coil to oppose changes in its own current), MUTUAL INDUCTANCE, the AC GENERATOR, and EDDY CURRENTS.


2. Magnetic Flux

  • Φ_B = B · A = BA cos θ. Unit: Weber (Wb).
  • 'Flux is the "amount" of magnetic field PASSING THROUGH a surface.'
  • Φ_B = NBA cos θ for an N-turn coil.

3. Faraday's Laws

First Law

  • 'Whenever the magnetic flux linked with a circuit CHANGES, an induced EMF is produced.'

Second Law

  • ε = −dΦ/dt (for a single turn). ε = −N dΦ/dt (for an N-turn coil).
  • 'The magnitude of the induced EMF equals the RATE OF CHANGE of magnetic flux.'

Methods of Changing Flux

  1. Change the magnetic field B.
  2. Change the area A of the loop.
  3. Change the angle θ between B and the normal to the loop.

4. Lenz's Law

  • 'The direction of induced current is such that it OPPOSES the CAUSE that produces it.'
  • ε = −dΦ/dt — the NEGATIVE SIGN IS LENZ'S LAW.
  • 'Lenz's law is ENERGY CONSERVATION in action. If induced current HELPED the change, we would get energy from nothing.'

Worked Example 1

Problem: A coil of 100 turns has a flux of 0.05 Wb through it. If the flux is reduced to zero in 0.1 s, find the induced EMF. Solution: ε = −N dΦ/dt = −100(0 − 0.05)/0.1 = −100(−0.5) = 50 V. 'The magnitude is 50 V.'


5. Self-Inductance

  • L = NΦ/I. 'The property of a coil to oppose changes in its own current.'
  • Induced EMF: ε = −L dI/dt.
  • Inductance of a solenoid: L = μ₀N²A/l.
  • Unit: Henry (H). 1 H = 1 Wb/A.

Energy Stored in an Inductor

  • U = ½ LI². 'An inductor stores energy in its MAGNETIC FIELD.'

6. Mutual Inductance

  • M = N₂Φ₂₁/I₁ = N₁Φ₁₂/I₂.
  • 'The flux through coil 2 due to current in coil 1 — divided by that current.'
  • Induced EMF: ε₂ = −M dI₁/dt.
  • M for two coaxial solenoids: M = μ₀N₁N₂A/l (if inner solenoid is inside outer one).

7. AC Generator

  • Principle: Electromagnetic induction — rotating a coil in a magnetic field.
  • EMF: ε = NBAω sin(ωt) = ε₀ sin(ωt). 'The EMF varies SINUSOIDALLY with time.'
  • Peak EMF: ε₀ = NBAω. RMS EMF: ε_rms = ε₀/√2.
ComponentFunction
Field magnetProvides uniform magnetic field (typically N and S poles)
Armature (coil)Rotates in the field — where EMF is induced
Slip ringsConnect rotating coil to external circuit — maintain contact
BrushesStationary contacts that press against slip rings

8. Eddy Currents

  • 'When a conducting material moves through a changing magnetic field, INDUCED CURRENTS flow within the material itself — like whirlpools in water.'
  • Effects: Heating (induction furnace), braking (eddy current brakes in trains), damping (galvanometer damping).
  • Minimising: Laminate the conductor (thin sheets insulated from each other) — breaks the path of eddy currents.

9. Comparison Table: Self-Inductance vs Mutual Inductance

FeatureSelf-Inductance (L)Mutual Inductance (M)
DefinitionOpposition to change in OWN currentEMF induced in ANOTHER coil due to change in THIS coil
SymbolLM
FormulaL = NΦ/IM = N₂Φ₂₁/I₁
Depends onOwn geometry and coreGeometry of BOTH coils, their separation, and core
UnitHenry (H)Henry (H)

10. Common Mistakes

  1. The negative sign in Faraday's law: It is NOT optional. It embodies LENZ'S LAW — the induced EMF opposes the change.
  2. Induced EMF vs induced current: Induced EMF depends ONLY on rate of change of flux. Induced current = EMF / resistance.
  3. Self-inductance formula: L = μ₀N²A/l — number of turns is SQUARED, not linear.
  4. AC generator EMF: Peak value = NBAω. RMS value = NBAω/√2. Many students forget the relationship.

11. CBSE Exam Focus

  1. Faraday's laws — magnitude of induced EMF (ε = −N dΦ/dt)
  2. Lenz's law — direction of induced current
  3. Self-inductance — L = μ₀N²A/l for solenoid, energy stored (½LI²)
  4. Mutual inductance — M for coaxial solenoids
  5. AC generator — construction, working, EMF = NBAω sin(ωt)
  6. Eddy currents — effects, applications, minimisation

12. Self-Test

Q1: A rectangular loop of area 0.1 m² is placed perpendicular to a uniform magnetic field of 0.5 T. The field is reduced to zero in 0.01 s. Find the induced EMF. A1: ε = −dΦ/dt = −(0 − 0.5×0.1)/0.01 = −(−0.05)/0.01 = 5 V.

Q2: A solenoid of length 0.5 m, area 4×10⁻⁴ m², and 1000 turns carries 2 A. Find its self-inductance. A2: L = μ₀N²A/l = (4π×10⁻⁷)(1000)²(4×10⁻⁴)/0.5 = (4π×10⁻⁷×10⁶×4×10⁻⁴)/0.5 = (4π×4×10⁻⁵)/0.5 = 16π×10⁻⁵/0.5 = 32π×10⁻⁵ = 1.005×10⁻³ H = 1 mH.

Q3: A 10 mH inductor has a current that changes from 5 A to 1 A in 0.02 s. Find the induced EMF. A3: ε = −L dI/dt = −10×10⁻³(1−5)/0.02 = −10⁻²(−4)/0.02 = 0.04/0.02 = 2 V.

Q4: An AC generator has 200 turns, area 0.05 m², in a 0.2 T field, rotating at 50 rad/s. Find peak and RMS EMF. A4: ε₀ = NBAω = 200×0.2×0.05×50 = 100 V. ε_rms = ε₀/√2 = 100/√2 = 70.7 V.

Q5: Two coils have mutual inductance 0.05 H. If the current in the primary changes from 4 A to 1 A in 0.01 s, find the induced EMF in the secondary. A5: ε₂ = −M dI₁/dt = −0.05(1−4)/0.01 = −0.05(−3)/0.01 = 0.15/0.01 = 15 V.


13. Conclusion

Electromagnetic induction is how we GENERATE electricity:

  • FARADAY: 'Change the flux — get an EMF. The RATE of change determines the VOLTAGE.'
  • LENZ: 'Nature OPPOSES change — the induced current tries to maintain the status quo.'
  • INDUCTANCE: 'A coil resists changes in current — the property of SELF-INDUCTANCE is electrical inertia.'
  • GENERATOR: 'Mechanical energy → Electrical energy. The reverse of a motor.'

'Electromagnetic induction is the PRINCIPLE behind the electric generator — and the reason our civilisation runs on electricity.'

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Faraday's law
emf = -N dPhi/dt; Phi = BA cos(theta)
The negative sign is Lenz's law.
Self-inductance
emf = -L dI/dt; L = mu0 N^2 A / l; U = (1/2) L I^2
Inductance of a solenoid; energy stored in the field.
Mutual inductance
emf2 = -M dI1/dt; M = mu0 N1 N2 A / l
For coaxial solenoids.
AC generator emf
emf = NBA omega sin(omega t); peak = NBA omega
RMS emf = peak/sqrt(2).
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Dropping the negative sign in Faraday's law
The minus sign embodies Lenz's law: the induced emf opposes the change in flux.
WATCH OUT
Confusing induced emf with induced current
Induced emf depends only on the rate of change of flux; the current is emf divided by resistance.
WATCH OUT
Using N instead of N squared for self-inductance
Self-inductance of a solenoid depends on N^2 (L = mu0 N^2 A/l).
WATCH OUT
Forgetting the peak-to-rms relation for generators
Peak emf = NBA omega and rms emf = peak/sqrt(2).

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Faraday
A 0.1 m^2 loop perpendicular to a 0.5 T field has the field reduced to zero in 0.01 s. Find the induced emf.
Show solution
emf = -dPhi/dt = -(0 - 0.5 x 0.1)/0.01 = 5 V.
Q2MEDIUM· Self-Inductance
A solenoid of length 0.5 m, area 4e-4 m^2, and 1000 turns. Find its self-inductance.
Show solution
L = mu0 N^2 A/l = 4 pi e-7 x (1000)^2 x 4e-4 / 0.5 approximately 1e-3 H = 1 mH.
Q3EASY· Inductor emf
A 10 mH inductor's current changes from 5 A to 1 A in 0.02 s. Find the induced emf.
Show solution
emf = -L dI/dt = -10e-3 x (1 - 5)/0.02 = 2 V.
Q4MEDIUM· Generator
An AC generator has 200 turns, area 0.05 m^2, field 0.2 T, rotating at 50 rad/s. Find peak and rms emf.
Show solution
Peak = NBA omega = 200 x 0.2 x 0.05 x 50 = 100 V. RMS = 100/sqrt(2) = 70.7 V.
Q5MEDIUM· Mutual Inductance
Two coils have M = 0.05 H. If the primary current changes from 4 A to 1 A in 0.01 s, find the secondary emf.
Show solution
emf2 = -M dI1/dt = -0.05 x (1 - 4)/0.01 = 15 V.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Magnetic flux Phi = BA cos(theta); unit weber.
  • Faraday: emf = -N dPhi/dt; change B, A, or theta to induce emf.
  • Lenz's law: induced current opposes the change (energy conservation).
  • Self-inductance L = mu0 N^2 A/l; energy U = (1/2) L I^2.
  • Mutual inductance M links two coils; emf2 = -M dI1/dt.
  • AC generator: emf = NBA omega sin(omega t); rms = peak/sqrt(2).
  • Eddy currents cause heating and braking; laminations reduce them.

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 6-8 marks across the chapter

Question typeMarks eachTypical countWhat it tests
Inductance / energy3-51Self/mutual inductance and stored energy
Faraday / Lenz31Induced emf and direction
Generator / eddy currents2-31AC generator and eddy-current effects
Prep strategy
  • Apply Faraday's law with the Lenz sign
  • Use Lenz's law to fix current direction
  • Remember N^2 in self-inductance
  • Relate peak and rms generator emf

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Power generation

AC generators in power plants convert mechanical energy into electricity via induction.

Transformers

Mutual induction steps voltage up or down for efficient power transmission.

Induction heating and braking

Eddy currents heat metals in induction cooktops and brake trains smoothly.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Apply Faraday's law including the negative sign
  2. Use Lenz's law to determine current direction
  3. Remember N^2 in the self-inductance formula
  4. State peak and rms emf for generators

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Analyse the growth and decay of current in an RL circuit.
  • Derive motional emf for a rod moving in a magnetic field and its power.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 12 Physics examHigh
JEE Main and Advanced (EM Induction)High
NEET PhysicsMedium

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

Lenz's law says the induced current always opposes the change in flux that produces it. If instead the induced current aided the change, it would strengthen the flux, which would induce an even larger current, and so on, creating energy from nothing. By opposing the change, the induced current makes us do work against the opposing force (for example, when pushing a magnet into a coil), and that mechanical work is what is converted into electrical energy. So Lenz's law is simply energy conservation expressed in electromagnetic terms, which is why Faraday's law carries a negative sign.

Eddy currents are loops of induced current that swirl within a solid conductor when it experiences a changing magnetic flux. They are useful for induction heating (furnaces and cooktops), electromagnetic braking in trains, and damping in instruments. However, in transformer and motor cores they dissipate energy as unwanted heat, reducing efficiency. To minimise this loss, cores are made of thin, insulated laminations stacked together, which break up the conducting paths and greatly reduce the eddy currents.
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Last reviewed on 30 May 2026. Written and reviewed by subject-matter experts — read about our process.
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