By the end of this chapter you'll be able to…

  • 1Apply the Biot-Savart law to straight wires and circular loops
  • 2Use Ampere's circuital law for solenoids and toroids
  • 3Compute the Lorentz force and motion of charges in a field
  • 4Find the force between parallel currents and torque on a loop
  • 5Explain the galvanometer and its conversion to ammeter/voltmeter
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Why this chapter matters
A moving charge creates a magnetic field, and a magnetic field exerts force on moving charges -- the unity at the heart of electromagnetism. Biot-Savart, Ampere's law, the Lorentz force, and the galvanometer underpin motors, meters, and modern technology.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Moving Charges and Magnetism

'Electricity and magnetism are two faces of the SAME coin — a moving charge creates a magnetic field, and a magnetic field affects moving charges.'

1. Chapter Overview

This chapter reveals the CONNECTION between electricity and magnetism. Topics include: the MAGNETIC FIELD due to a current-carrying wire (Biot-Savart law), AMPERE'S CIRCUITAL LAW (magnetic equivalent of Gauss's law), the FORCE on a moving charge in a magnetic field (Lorentz force), the FORCE between two parallel current-carrying wires, the TORQUE on a current loop in a magnetic field, and the MOVING COIL GALVANOMETER.


2. Biot-Savart Law

  • Magnetic field due to a current element: dB⃗ = (μ₀/4π) (I dl⃗ × r̂)/r²
  • μ₀ = 4π × 10⁻⁷ T·m/A (permeability of free space).

Magnetic Field Due to a Long Straight Wire

  • B = μ₀I/(2πr). 'The field circles the wire — strength decreases as 1/r.'

Magnetic Field at the Centre of a Circular Loop

  • B = μ₀I/(2R) (for a single turn). B = μ₀nI/(2R) for n turns.
  • 'Right-hand rule: Curl your fingers along B, thumb in direction of current.'

Magnetic Field on the Axis of a Circular Loop

  • B = μ₀IR²/[2(R² + x²)³/²] — at centre (x=0): B = μ₀I/(2R).

3. Ampere's Circuital Law

  • ∮ B⃗ · dl⃗ = μ₀ I_enc. 'The line integral of B around a closed loop equals μ₀ times the current enclosed.'
  • 'Ampere's law is to magnetism what Gauss's law is to electrostatics — a powerful symmetry tool.'

Applications

ConfigurationMagnetic FieldAmperian Loop
Infinite straight wireB = μ₀I/(2πr)Circle centred on wire
Solenoid (ideal)B = μ₀nI inside, 0 outsideRectangular loop
ToroidB = μ₀NI/(2πr)Circle inside toroid

4. Force on a Moving Charge — Lorentz Force

  • F = q(E + v × B). 'The total electromagnetic force on a charge.'
  • Magnetic force only: F = q(v × B). Magnitude: F = qvB sin θ.
  • Direction: PERPENDICULAR to BOTH v and B (right-hand rule).
  • 'The magnetic force NEVER does work — it always acts perpendicular to velocity, changing only DIRECTION, not speed.'

Motion in a Uniform Magnetic Field

  • v ⟂ B: CIRCULAR motion. Radius r = mv/(qB). Period T = 2πm/(qB).
  • v ∥ B: STRAIGHT LINE (no force).
  • v at angle θ: HELICAL path.

5. Force on a Current-Carrying Conductor

  • F = I(L × B). F = ILB sin θ.
  • Force between two parallel wires: F/L = μ₀I₁I₂/(2πd).
    • SAME direction → ATTRACT. OPPOSITE direction → REPEL.
    • 'This force DEFINES the Ampere — the unit of current.'

6. Torque on a Current Loop

  • τ = N I A B sin θ (where θ is angle between normal to loop and B).
  • Magnetic dipole moment: m = N I A (direction: along the normal per right-hand rule).
  • τ = m × B. 'A current loop behaves like a magnetic dipole — it ALIGNS with the external field.'

7. Moving Coil Galvanometer (MCG)

  • Principle: Torque on a current-carrying coil in a magnetic field.
  • Current sensitivity: S_I = θ/I = NBA/k (k = torsion constant).
  • Voltage sensitivity: S_V = θ/V = NBA/(kR_g).
  • Conversion: Galvanometer → Ammeter: Add a LOW RESISTANCE SHUNT in PARALLEL. Galvanometer → Voltmeter: Add a HIGH RESISTANCE in SERIES.
InstrumentHow to ConvertKey Formula
Galvanometer to AmmeterShunt (low R) in parallelS = I_g·G/(I − I_g)
Galvanometer to VoltmeterHigh R in seriesR = V/I_g − G

8. Comparison Table: Electric Field vs Magnetic Field

PropertyElectric Field (E)Magnetic Field (B)
SourceStationary chargesMoving charges / currents
Force on charge qF = qE (parallel to E)F = q(v×B) (perp to v and B)
LinesStart/end at chargesCLOSED LOOPS (no monopoles)
Work doneCan do workZERO work (perp to velocity)
Flux lawGauss: Φ_E = q/ε₀Gauss: Φ_B = 0 (no monopoles)
Circulation lawConservative: ∮E·dl = 0Ampere: ∮B·dl = μ₀I

9. Common Mistakes

  1. Direction of magnetic force: Use the RIGHT-HAND RULE. Thumb = velocity (or current), fingers = B, palm = force. For negative charges, REVERSE the direction.
  2. Magnetic field direction around a wire: NOT radial — it is CIRCULAR (circles around the wire). Unlike E which is radial.
  3. Solenoid formula: B = μ₀nI, where n = N/L (turns per unit length). Do NOT use N alone.
  4. Ammeter and voltmeter connections: Ammeter in SERIES (low resistance). Voltmeter in PARALLEL (high resistance). Shunt for ammeter, multiplier for voltmeter.

10. CBSE Exam Focus

  1. Biot-Savart law — field due to straight wire, circular loop
  2. Ampere's circuital law — field due to solenoid, toroid
  3. Lorentz force — force on a moving charge, cyclotron radius
  4. Force between two parallel current-carrying wires
  5. Torque on a current loop — magnetic dipole moment
  6. Galvanometer — conversion to ammeter and voltmeter (SHUNT and MULTIPLIER)

11. Self-Test

Q1: A long straight wire carries 5 A. Find B at a distance of 10 cm from the wire. A1: B = μ₀I/(2πr) = (4π×10⁻⁷)(5)/(2π×0.1) = (2×10⁻⁷×5)/0.1 = 10⁻⁵ T.

Q2: A proton (q=1.6×10⁻¹⁹ C, m=1.67×10⁻²⁷ kg) moves perpendicular to a 0.5 T field at 2×10⁶ m/s. Find the radius of its path. A2: r = mv/(qB) = (1.67×10⁻²⁷×2×10⁶)/(1.6×10⁻¹⁹×0.5) = (3.34×10⁻²¹)/(8×10⁻²⁰) = 0.04175 m = 4.18 cm.

Q3: A solenoid has 1000 turns per metre and carries 2 A. Find B inside. A3: B = μ₀nI = (4π×10⁻⁷)(1000)(2) = 8π×10⁻⁴ T ≈ 2.51×10⁻³ T.

Q4: A galvanometer has G = 50 Ω and gives full-scale deflection for I_g = 5 mA. Convert it to an ammeter of range 5 A. A4: S = I_g·G/(I − I_g) = (5×10⁻³×50)/(5 − 0.005) = 0.25/4.995 = 0.05 Ω ≈ 0.05 Ω (shunt).

Q5: Two long parallel wires carry 3 A and 4 A in the SAME direction, 5 cm apart. Find the force per unit length between them. A5: F/L = μ₀I₁I₂/(2πd) = (4π×10⁻⁷×3×4)/(2π×0.05) = (4π×10⁻⁷×12)/(0.1π) = 48×10⁻⁷/0.1 = 4.8×10⁻⁵ N/m (ATTRACTIVE).


12. Conclusion

Moving charges and magnetism UNIFY electricity and magnetism:

  • BIOT-SAVART: 'The building block — current elements produce magnetic fields.'
  • AMPERE'S LAW: 'Sum up the field around a closed path — equals μ₀ × current enclosed.'
  • LORENTZ FORCE: 'The force on a moving charge — the basis of electric motors and generators.'
  • GALVANOMETER: 'Current measured through torque on a coil — the heart of analog meters.'

'Where charges move, magnetic fields appear. Where magnetic fields change, currents flow. This INSEPARABLE pair is electromagnetism.'

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Biot-Savart and straight wire
dB = (mu0/4pi)(I dl x r_hat)/r^2; B = mu0 I/(2 pi r)
Field circles a straight wire.
Loop and solenoid fields
Loop centre B = mu0 I/(2R); solenoid B = mu0 n I
n is turns per unit length.
Lorentz force and radius
F = q(v x B); r = mv/(qB); T = 2 pi m/(qB)
Magnetic force does no work.
Force between wires; torque
F/L = mu0 I1 I2/(2 pi d); torque = NIAB sin(theta)
Parallel currents attract; magnetic moment m = NIA.
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Treating the magnetic field around a wire as radial
The field forms closed circles around the wire, unlike the radial electric field.
WATCH OUT
Thinking the magnetic force does work
The magnetic force is always perpendicular to velocity, so it changes direction but not speed and does zero work.
WATCH OUT
Using N instead of n in the solenoid formula
B = mu0 n I uses n = N/L (turns per unit length), not the total number of turns.
WATCH OUT
Swapping ammeter and voltmeter conversions
A galvanometer becomes an ammeter with a low-resistance shunt in parallel and a voltmeter with a high resistance in series.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Straight Wire
A long straight wire carries 5 A. Find B at 10 cm from the wire.
Show solution
B = mu0 I/(2 pi r) = (2e-7 x 5)/0.1 = 1e-5 T.
Q2MEDIUM· Lorentz
A proton (m = 1.67e-27 kg, q = 1.6e-19 C) moves at 2e6 m/s perpendicular to a 0.5 T field. Find the radius.
Show solution
r = mv/(qB) = (1.67e-27 x 2e6)/(1.6e-19 x 0.5) = 0.042 m = 4.18 cm.
Q3EASY· Solenoid
A solenoid has 1000 turns/m and carries 2 A. Find B inside.
Show solution
B = mu0 n I = 4 pi e-7 x 1000 x 2 = 2.51e-3 T.
Q4MEDIUM· Galvanometer
A galvanometer (G = 50 ohm, full scale at 5 mA) is converted to a 5 A ammeter. Find the shunt.
Show solution
S = Ig G/(I - Ig) = (5e-3 x 50)/(5 - 0.005) = 0.25/4.995 approximately 0.05 ohm.
Q5MEDIUM· Parallel Wires
Two parallel wires carry 3 A and 4 A in the same direction, 5 cm apart. Find force per unit length.
Show solution
F/L = mu0 I1 I2/(2 pi d) = (2e-7 x 12)/0.05 = 4.8e-5 N/m, attractive.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Biot-Savart: dB = (mu0/4pi)(I dl x r_hat)/r^2.
  • Straight wire B = mu0 I/(2 pi r); loop centre B = mu0 I/(2R).
  • Ampere's law: integral B.dl = mu0 I_enclosed; solenoid B = mu0 n I.
  • Lorentz force F = q(E + v x B); magnetic part does no work.
  • Charge in field: r = mv/(qB), period independent of speed.
  • Parallel currents: same direction attract, opposite repel; defines the ampere.
  • Torque on a loop = NIAB sin(theta); galvanometer to ammeter (shunt) or voltmeter (series resistance).

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 7-9 marks across the chapter

Question typeMarks eachTypical countWhat it tests
Biot-Savart / Ampere3-51Fields of wires, loops, solenoids
Lorentz force / motion31Force and circular/helical motion
Galvanometer / torque2-31Meter conversion and loop torque
Prep strategy
  • Use the right-hand rule for field and force directions
  • Apply Ampere's law with a suitable Amperian loop
  • Remember magnetic force does no work
  • Learn shunt and multiplier formulas for meters

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Electric motors

Torque on current loops in magnetic fields drives motors and actuators.

Measuring instruments

Moving-coil galvanometers form the basis of analog ammeters and voltmeters.

Particle physics and medicine

Magnetic fields steer charged particles in cyclotrons and MRI machines.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Apply the right-hand rule consistently for directions
  2. Choose Amperian loops matching the symmetry
  3. Use r = mv/qB for charged-particle motion
  4. Apply shunt/multiplier formulas for meter conversion

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Analyse the cyclotron and velocity selector quantitatively.
  • Derive the field on the axis of a finite solenoid.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 12 Physics examHigh
JEE Main and Advanced (Magnetic Effects)High
NEET PhysicsHigh

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

The magnetic force F = q(v x B) is always perpendicular to the velocity v, by the nature of the cross product. Work done is the dot product of force and displacement, and since the force is perpendicular to the direction of motion at every instant, this dot product is zero. So the magnetic force can change the direction of a charged particle's motion (bending it into circles or helices) but never changes its speed or kinetic energy.

A galvanometer is a sensitive device that deflects for tiny currents. To make an ammeter, which must carry large currents, a small resistance called a shunt is connected in parallel; it diverts most of the current and gives the combination a low overall resistance suitable for series connection. To make a voltmeter, which must not draw much current, a large resistance (multiplier) is connected in series; this gives a high total resistance so the voltmeter can be placed in parallel across a component and read the voltage with minimal disturbance.
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Last reviewed on 30 May 2026. Written and reviewed by subject-matter experts — read about our process.
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