By the end of this chapter you'll be able to…

  • 1State and apply the Pythagoras-Baudhayana theorem
  • 2Find missing sides in right-angled triangles
  • 3Recognise and use famous Pythagorean triples
  • 4Verify whether a triangle is right-angled
  • 5Appreciate India's historical contribution
💡
Why this chapter matters
One of the most important theorems in mathematics. a² + b² = c² appears in geometry, trigonometry, coordinate geometry, physics, and engineering. Indian heritage: Baudhayana (~800 BCE) gave the theorem 300 years before Pythagoras.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

The Baudhayana–Pythagoras Theorem — Class 8 Mathematics (Ganita Prakash)

"In a right-angled triangle, the area of the square on the diagonal is equal to the sum of the areas of the squares on the two sides." — Baudhayana, Sulba Sutras (~800 BCE)

1. About the Chapter

This chapter introduces one of the most important and elegant theorems in mathematics. Ganita Prakash deliberately credits Baudhayana (Indian sage, ~800 BCE) alongside Pythagoras (Greek mathematician, ~500 BCE) — recognising that the result was known in India 300 years before Pythagoras.

The Theorem (in modern words)

In a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) equals the sum of the squares of the other two sides.

If a, b are the two legs and c is the hypotenuse: a² + b² = c²


2. Historical Context

Baudhayana (~800 BCE)

  • Indian sage, author of 'Baudhayana Sulba Sutra'
  • Used the theorem for fire-altar construction
  • His statement: "The diagonal of a rectangle produces both the lengths of the sides separately"
  • Discovered the theorem and several Pythagorean triples

Pythagoras (~570-495 BCE)

  • Greek philosopher and mathematician
  • Founded the Pythagorean school in Croton, Italy
  • His students gave the first PROOF of the theorem
  • Therefore the theorem bears his name in the Western tradition

Other Cultures

  • Babylonian clay tablets (~1900 BCE) show knowledge of the relationship
  • Chinese 'Zhou Bi Suan Jing' (~500 BCE) also has the theorem
  • It is one of the earliest universal mathematical discoveries

Why Both Names?

The theorem was independently discovered in MANY ancient civilisations. The Indian (Baudhayana) and Greek (Pythagoras) versions are best documented. Modern Indian textbooks honour both — recognising India's contribution.


3. The Theorem — Detailed Understanding

Setting up the Right Triangle

A right-angled triangle has one angle = 90°. The side opposite this angle is the hypotenuse (the LONGEST side). The other two sides are called legs or catheti.

        |\
        | \
        |  \  hypotenuse (c)
   leg  |   \
    (b) |    \
        |_____\
          leg
          (a)

Statement

For ANY right-angled triangle: a² + b² = c²

where:

  • a = one leg
  • b = other leg
  • c = hypotenuse

Converse

If a² + b² = c² for some triangle, then the triangle is right-angled (with the right angle opposite to c).

This is used to verify if a triangle is right-angled.


4. Pythagorean Triples

Definition

A Pythagorean triple is a set of three positive integers (a, b, c) such that a² + b² = c².

Famous Triples

  • (3, 4, 5) — most famous! 3² + 4² = 9 + 16 = 25 = 5² ✓
  • (5, 12, 13) — 25 + 144 = 169 = 13² ✓
  • (8, 15, 17) — 64 + 225 = 289 = 17² ✓
  • (7, 24, 25) — 49 + 576 = 625 = 25² ✓
  • (9, 40, 41) — 81 + 1600 = 1681 = 41² ✓
  • (20, 21, 29) — 400 + 441 = 841 = 29² ✓

Memorise These

Knowing these triples lets you solve Pythagoras problems instantly without calculation.

Multiples Also Work

If (a, b, c) is a Pythagorean triple, so is (ka, kb, kc) for any positive integer k.

  • (3, 4, 5) → (6, 8, 10), (9, 12, 15), (12, 16, 20), (15, 20, 25)
  • (5, 12, 13) → (10, 24, 26), (15, 36, 39)

Indian Contribution

Baudhayana listed several Pythagorean triples in the Sulba Sutras — including some non-trivial ones used in altar construction.


5. Proofs of the Theorem

The theorem has HUNDREDS of distinct proofs (more than any other theorem!). Here are two simple ones.

Proof 1: Algebraic / Area Method

Take a large square of side (a + b). Inside, arrange 4 right-angled triangles (each with legs a and b) such that they enclose a smaller square of side c (the hypotenuse).

  • Total square area = (a + b)² = a² + 2ab + b²
  • Sum of parts = 4 × (1/2)ab + c² = 2ab + c²
  • Setting equal: a² + 2ab + b² = 2ab + c²
  • Cancel 2ab: a² + b² = c²

Proof 2: Similar Triangles

Drop a perpendicular from the right angle to the hypotenuse, dividing the triangle into two smaller right-angled triangles. By similarity:

  • Each smaller triangle is similar to the original.
  • Ratios of sides give the Pythagorean relation.

6. Applications — Finding the Missing Side

Type 1: Find the Hypotenuse

Given a and b, find c. c = √(a² + b²)

Example: Legs 6 cm and 8 cm. Find hypotenuse.

  • c² = 6² + 8² = 36 + 64 = 100
  • c = 10 cm ✓ (This is (6,8,10) — a multiple of (3,4,5))

Type 2: Find a Leg

Given hypotenuse c and one leg, find the other. a = √(c² − b²)

Example: Hypotenuse 13, one leg 5. Find other leg.

  • a² = 13² − 5² = 169 − 25 = 144
  • a = 12 ✓ (This is (5,12,13))

Type 3: Check if Right-Angled

Given three sides, check if a² + b² = c² (where c is the largest).

Example: Triangle with sides 9, 12, 15. Right-angled?

  • Largest = 15.
  • 9² + 12² = 81 + 144 = 225 = 15² ✓
  • YES, right-angled.

7. Real-World Applications

Construction

  • Carpenters check if corners are square: measure 3 units along one wall, 4 along the perpendicular. If the diagonal is 5 units, the corner is exactly 90°.

Surveying

  • Measure distances across rivers, mountains using right triangles.
  • Find straight-line distance between two points whose horizontal and vertical separations are known.
  • "If you walk 9 km east and then 12 km north, you are 15 km from where you started" (using 9-12-15 triple).

Architecture

  • Stairs: rise² + run² = step length²
  • Roof pitch: relates rise, run, and slope length

Engineering

  • Trusses in bridges use right triangles
  • Cable lengths in suspension bridges calculated via Pythagoras
  • TV screen diagonal: width² + height² = diagonal²

Modern Examples

  • GPS positioning uses Pythagoras-like calculations
  • 3D rendering (video games) uses Pythagoras for distances
  • Robotics uses it for path planning

8. Worked Examples

Example 1: Find Hypotenuse

Triangle with legs 9 and 40. Find hypotenuse.

  • c² = 9² + 40² = 81 + 1600 = 1681
  • c = √1681 = 41
  • Recognise (9, 40, 41) Pythagorean triple ✓

Example 2: Find Leg

Hypotenuse 17, one leg 8. Find other.

  • b² = 17² − 8² = 289 − 64 = 225
  • b = 15
  • Recognise (8, 15, 17) triple ✓

Example 3: Check Right-Angled

Triangle with sides 8, 15, 17. Is it right-angled?

  • Largest is 17. Check 8² + 15² = 64 + 225 = 289 = 17² ✓
  • YES — and the right angle is opposite the side of length 17.

Example 4: Real-World

A ladder of length 13 m is leaning against a wall. The foot is 5 m from the wall. How high up does it reach?

  • Hypotenuse (ladder) = 13, base (along ground) = 5.
  • Height² = 13² − 5² = 169 − 25 = 144
  • Height = 12 m

Example 5: Diagonal of Rectangle

A rectangle is 24 m × 7 m. Find the diagonal.

  • Diagonal² = 24² + 7² = 576 + 49 = 625
  • Diagonal = 25 m (using (7, 24, 25))

Example 6: Diagonal of Square

A square has side 10 cm. Find the diagonal.

  • Diagonal² = 10² + 10² = 200
  • Diagonal = √200 = 10√2 ≈ 14.14 cm

Example 7: Distance Between Points

A boy walks 6 km east and then 8 km south. How far is he from the starting point?

  • Treat as right triangle: legs 6 and 8.
  • Distance = √(6² + 8²) = √100 = 10 km ✓ (3,4,5 multiple)

Example 8: Find Missing Pythagorean Triple

Find c so that (20, 21, c) is a Pythagorean triple.

  • c² = 20² + 21² = 400 + 441 = 841
  • c = 29 ✓ (This IS the (20, 21, 29) triple)

9. Common Mistakes

  1. Adding sides instead of squares

    • WRONG: a + b = c (for right triangle)
    • CORRECT: a² + b² = c²
  2. Identifying wrong side as hypotenuse

    • Hypotenuse is OPPOSITE the right angle (NOT longest side because it can be ambiguous in obtuse triangles)
    • In a right triangle, hypotenuse IS the longest side
  3. Using theorem for non-right triangles

    • The theorem ONLY works for RIGHT-angled triangles
    • For other triangles, use the cosine law
  4. Confusing positive and negative roots

    • Sides are positive — take only positive square root
  5. Forgetting square roots when finding sides

    • If a² = 144, then a = 12 (not 144!)

10. Tips for Mastery

Memorise Pythagorean Triples

  • (3, 4, 5) and its multiples
  • (5, 12, 13)
  • (8, 15, 17)
  • (7, 24, 25)
  • (9, 40, 41)
  • (20, 21, 29)

These will let you solve many problems INSTANTLY.

Recognise Multiples

  • (6, 8, 10) is just 2×(3, 4, 5)
  • (15, 36, 39) is 3×(5, 12, 13)
  • (12, 16, 20) is 4×(3, 4, 5)

Practice

  • Solve 5 'find hypotenuse' problems
  • Solve 5 'find leg' problems
  • Solve 5 word problems
  • Solve 5 'check if right-angled' problems

11. Beyond Class 8 — Where Next?

The Pythagoras-Baudhayana theorem leads directly to:

  • Class 9 Coordinate Geometry: distance between two points = √((x₂−x₁)² + (y₂−y₁)²)
  • Class 10 Trigonometry: sin² θ + cos² θ = 1 (a form of Pythagoras)
  • Class 11 3D Geometry: extends to 3D distance: √(x² + y² + z²)
  • Higher mathematics: vectors, complex numbers, all use this idea

It is genuinely one of the most universal theorems in mathematics.


12. Conclusion

The Baudhayana–Pythagoras theorem is a gift from ancient mathematicians to all subsequent generations. Discovered by Baudhayana in India around 800 BCE for sacred geometry, proved by Pythagoras' Greek school around 500 BCE for academic mathematics, and rediscovered independently by many civilisations, it has become one of the most-used theorems in human history.

Master it deeply. Memorise the famous Pythagorean triples. Practise applications. This theorem will appear in virtually every later mathematics, science, and engineering course you take.

And remember: when you write a² + b² = c², you are using a piece of Indian mathematical heritage — a 2800-year-old discovery that helped build temples, navigate seas, and design modern cities.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Theorem
a² + b² = c²
c = hypotenuse
Find hypotenuse
c = √(a² + b²)
Find leg
a = √(c² − b²)
Converse
If a² + b² = c², triangle is right-angled (with right angle opposite c)
Square diagonal
d = s√2 where s is side
Rectangle diagonal
d = √(L² + B²)
⚠️

Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Adding sides instead of squares
a + b ≠ c. Must square first: a² + b² = c².
WATCH OUT
Wrong identification of hypotenuse
Hypotenuse is OPPOSITE the right angle. It is the LONGEST side of a right-angled triangle.
WATCH OUT
Forgetting square root
If c² = 169, then c = 13 (not 169). Always take square root for the side length.
WATCH OUT
Using theorem on non-right triangle
Pythagoras applies ONLY to right-angled triangles. For others, use the cosine law (Class 10).
WATCH OUT
Taking negative root
Side lengths are POSITIVE. Take only the positive square root.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Hypotenuse
Find the hypotenuse of a right triangle with legs 3 cm and 4 cm.
Show solution
✦ Answer: c² = 3² + 4² = 9 + 16 = 25; c = 5 cm. (The famous 3-4-5 Pythagorean triple.)
Q2EASY· Triple
Is (5, 12, 13) a Pythagorean triple?
Show solution
✦ Answer: 5² + 12² = 25 + 144 = 169 = 13². Yes, it IS a Pythagorean triple.
Q3MEDIUM· Leg
A ladder is leaning against a wall. The foot is 9 m from the wall, and the top reaches 12 m up. How long is the ladder?
Show solution
Step 1 — Identify the right triangle. Wall is vertical, ground is horizontal — they meet at 90°. The ladder is the hypotenuse. Step 2 — Apply Pythagoras. Ladder² = 9² + 12² = 81 + 144 = 225 Ladder = √225 = 15 m Step 3 — Recognise the triple. (9, 12, 15) is 3 × (3, 4, 5) — a Pythagorean triple multiple. Step 4 — Verify. 9² + 12² = 81 + 144 = 225 = 15² ✓ ✦ Answer: The ladder is 15 m long.
Q4MEDIUM· Application
A man walks 12 km east, then 5 km north. How far is he from the starting point (straight-line distance)?
Show solution
Step 1 — Visualise. East and north are perpendicular. The path forms two legs of a right triangle. Straight-line distance is the hypotenuse. Step 2 — Apply Pythagoras. Distance² = 12² + 5² = 144 + 25 = 169 Distance = √169 = 13 km Step 3 — Recognise (5, 12, 13) triple. This is a classic Pythagorean triple. Memorise it. Step 4 — Sanity check. 13 km is less than 17 km (12 + 5) — yes, the straight line is shorter than the walked path (triangle inequality). ✦ Answer: The man is 13 km from the starting point.
Q5HARD· Real-world
A rectangular field is 80 m long and 60 m wide. A diagonal path is built across the field. (a) Find the length of the path. (b) If walking pace is 5 km/h, how long (in minutes) does it take to walk diagonally?
Show solution
Part (a) — Find the diagonal. Diagonal² = 80² + 60² = 6400 + 3600 = 10000 Diagonal = √10000 = 100 m Recognise the triple: (60, 80, 100) = 20 × (3, 4, 5). Confirmed. Part (b) — Convert and compute time. Walking pace: 5 km/h = 5000 m/h Convert to m/min: 5000 / 60 ≈ 83.33 m/min Time = Distance / Speed = 100 / 83.33 ≈ 1.2 minutes Or equivalently: 1 minute 12 seconds Step — Verify. In 1.2 min at 83.33 m/min: 1.2 × 83.33 = 100 m ✓ ✦ Answer: (a) Diagonal path = 100 m. (b) It takes about 1.2 minutes (1 min 12 s) to walk diagonally.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Theorem: a² + b² = c² in a right-angled triangle
  • Hypotenuse = side opposite the right angle = longest side
  • Converse: a² + b² = c² ⟹ right-angled triangle
  • Pythagorean triples: (3,4,5), (5,12,13), (8,15,17), (7,24,25), (9,40,41), (20,21,29)
  • Multiples of triples are also triples
  • Indian heritage: Baudhayana (~800 BCE) Sulba Sutras
  • Pythagoras (~500 BCE) gave the first PROOF
  • Square diagonal = side × √2
  • Rectangle diagonal = √(L² + B²)

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 10-12 marks per chapter

Question typeMarks eachTypical countWhat it tests
MCQ / Very Short12-3Statement of theorem; Pythagorean triple recognition
Short Answer32Find sides; verify right angle
Long Answer51-2Word problems; combination with other concepts
Prep strategy
  • Memorise the theorem: a² + b² = c²
  • Memorise the 6 famous Pythagorean triples (3-4-5, 5-12-13, 8-15-17, 7-24-25, 9-40-41, 20-21-29)
  • Recognise multiples of these triples (e.g., 9-12-15)
  • Practise finding both hypotenuse and leg
  • Solve 5 real-world word problems
  • Mention Baudhayana (~800 BCE) for Indian heritage marks

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Construction and carpentry

Builders use the 3-4-5 rule to ensure right angles. Mark 3 ft along one wall, 4 ft along the next; if diagonal is 5 ft, corner is square.

GPS and navigation

Modern GPS uses spherical Pythagoras to calculate distances. Basic GPS works on Pythagorean coordinate distances.

Video games and animation

3D distance calculations (player to enemy, object to target) use Pythagoras. Pathfinding algorithms rely on it.

Astronomy

Parallax calculations to measure star distances use Pythagoras in right triangles formed by Earth's orbit.

Indian heritage — Sulba Sutras

Sulba Sutras (~800 BCE) used Pythagorean relationships for precise fire-altar construction. India's first geometry textbook.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. ALWAYS write a² + b² = c² at the start
  2. IDENTIFY hypotenuse (opposite right angle, longest side)
  3. Use Pythagorean triples for INSTANT answers
  4. For 'is it right-angled?' problems, check largest² = sum of other two²
  5. Show all steps; verify answer is positive
  6. For real-world problems, draw a clear diagram first

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Euclid's formula for generating triples: (m²−n², 2mn, m²+n²)
  • Fermat's Last Theorem: aⁿ + bⁿ = cⁿ has no integer solutions for n > 2
  • Heron's formula for triangle area
  • Stewart's theorem (generalisation)
  • Apollonius's theorem (relates median and sides)

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 8 School ExamVery High
Class 8 OlympiadVery High
NTSEVery High
Class 9 Coordinate GeometryVery High — distance formula
Class 10 TrigonometryVery High
JEE FoundationVery High

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

Pythagoras' school in Greece (around 500 BCE) gave the first KNOWN PROOF of the theorem. Baudhayana (around 800 BCE) STATED the theorem (300 years earlier) but did not provide a formal proof. In Western mathematical tradition, theorems are usually named after the prover, not the discoverer. However, modern Indian textbooks rightfully credit Baudhayana — recognising India's role. Hence the name 'Baudhayana-Pythagoras Theorem' in Ganita Prakash.

Triples were discovered through observation and exploration of right triangles. (3,4,5) is the smallest non-trivial triple — likely discovered very early by builders. Euclid's formula generates all primitive triples: if m > n > 0, then a = m² − n², b = 2mn, c = m² + n² is a Pythagorean triple. Baudhayana listed several triples without a formula; Pythagoras and Euclid systematised the generation.

Yes! In 3D, the diagonal of a rectangular box with sides a, b, c has length d = √(a² + b² + c²). This is just Pythagoras applied twice: first find the diagonal of one face, then combine with the third side. This 3D Pythagoras is essential in physics, computer graphics, and 3D modelling.
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Last reviewed on 20 May 2026. Written and reviewed by subject-matter experts — read about our process.
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