Operations on Numbers
1. Addition — Combining Numbers
Addition of Large Numbers
Align digits by place value. Add column by column from the RIGHT. Carry when sum exceeds 9.
2 3 4 5 6 7 8
+ 1 9 8 7 6 5 4
----------------
4 3 3 3 3 3 2
'Start from the ones place. If the sum is 10 or more, CARRY the extra digit to the next column on the LEFT.'
Properties of Addition
| Property | Explanation | Example |
|---|---|---|
| Commutative | Changing order does NOT change sum | 25 + 30 = 30 + 25 |
| Associative | Changing grouping does NOT change sum | (5 + 9) + 6 = 5 + (9 + 6) |
| Identity | Zero added to a number gives the same number | 437 + 0 = 437 |
| Property of 10 | Adding 10 increases the tens digit by 1 | 456 + 10 = 466 |
Estimation in Addition
Round each number to the nearest thousand, then add.
4,279 + 3,612 ≈ 4,000 + 4,000 = 8,000 (Actual sum = 7,891 — close!)
2. Subtraction — Finding the Difference
Subtraction of Large Numbers
Align digits by place value. Subtract column by column from the RIGHT. Borrow when needed.
7 8 9 3 4 5
− 4 5 6 7 8 9
-------------
3 3 2 5 5 6
'When you borrow from the next column, that column's digit decreases by ONE, and the current column gets TEN added to it.'
Properties of Subtraction
| Property | Explanation | Example |
|---|---|---|
| NOT commutative | 7 − 5 ≠ 5 − 7 | Order matters! |
| Subtracting zero | Any number minus zero = itself | 834 − 0 = 834 |
| Subtracting itself | Any number minus itself = zero | 834 − 834 = 0 |
| Relation to addition | Difference + subtrahend = minuend | 345 − 123 = 222, so 222 + 123 = 345 |
Checking Subtraction Using Addition
'Always check your subtraction by ADDING the answer to the number you subtracted. You should get the original number back.'
3. Multiplication — Repeated Addition
Multiplication of Large Numbers
2-digit × 2-digit:
4 5
× 3 6
-----
2 7 0 (45 × 6)
1 3 5 0 (45 × 30)
--------
1 6 2 0
'Multiply by the ones digit first. Then multiply by the tens digit — remember to PLACE A ZERO in the ones column. Add the partial products.'
Properties of Multiplication
| Property | Explanation | Example |
|---|---|---|
| Commutative | 5 × 7 = 7 × 5 | Order does not matter |
| Associative | (2 × 3) × 4 = 2 × (3 × 4) | Grouping does not matter |
| Identity | Multiplying by 1 gives the same number | 89 × 1 = 89 |
| Zero property | Multiplying by 0 gives 0 | 56 × 0 = 0 |
| Distributive | a × (b + c) = a × b + a × c | 4 × (10 + 2) = 4 × 10 + 4 × 2 = 48 |
Multiplying by 10, 100, 1000
| Multiply By | How To | Example |
|---|---|---|
| 10 | Add ONE zero | 45 × 10 = 450 |
| 100 | Add TWO zeros | 45 × 100 = 4,500 |
| 1000 | Add THREE zeros | 45 × 1000 = 45,000 |
'To multiply by 10, 100, or 1000 — just COUNT the zeros and add them to the end of the number.'
4. Division — Sharing Equally
Terms of Division
Dividend ÷ Divisor = Quotient + Remainder
'Check: Dividend = Divisor × Quotient + Remainder. The remainder must ALWAYS be less than the divisor.'
Long Division
3 4 2 R 1
───────────
5 ) 1 7 1 1
− 1 5 ↓
────
2 1
− 2 0
───
1 1
− 1 0
───
1
'Bring down digits ONE at a time. Divide, multiply, subtract, bring down — repeat until no digits remain.'
Properties of Division
| Property | Explanation | Example |
|---|---|---|
| NOT commutative | 10 ÷ 2 ≠ 2 ÷ 10 | Order matters |
| Dividing by 1 | Any number ÷ 1 = itself | 56 ÷ 1 = 56 |
| Dividing by itself | Any number ÷ itself = 1 (except 0) | 25 ÷ 25 = 1 |
| Dividing zero | 0 ÷ any number = 0 | 0 ÷ 7 = 0 |
| Cannot divide by zero | Division by zero is UNDEFINED | 8 ÷ 0 has no meaning |
5. BODMAS — Order of Operations
When an expression has MULTIPLE operations, follow this order:
| Letter | Stands For | Example |
|---|---|---|
| B | Brackets (solve inside FIRST) | (4 + 3) × 2 = 7 × 2 = 14 |
| O | Of (multiplication with 'of') | Half of 20 = 10 |
| D | Division (left to right) | 12 ÷ 3 × 2 = 4 × 2 = 8 |
| M | Multiplication (left to right) | 4 × 3 + 5 = 12 + 5 = 17 |
| A | Addition (left to right) | 10 + 5 − 3 = 12 |
| S | Subtraction (left to right) | 15 − 4 + 2 = 13 |
'BRACKETS FIRST — ALWAYS. If there are nested brackets, solve the INNERMOST bracket first.'
Example: 15 − [2 + (6 − 4) × 3]
Step 1: Solve innermost bracket (6 − 4) = 2 Step 2: Multiply 2 × 3 = 6 Step 3: Add 2 + 6 = 8 Step 4: Subtract 15 − 8 = 7
6. Word Problems — Step by Step
Strategy
| Step | Action |
|---|---|
| 1 | Read the problem CAREFULLY — twice |
| 2 | Identify what is GIVEN and what is ASKED |
| 3 | Decide which OPERATION to use |
| 4 | ESTIMATE the answer first |
| 5 | SOLVE accurately |
| 6 | CHECK if the answer makes sense |
Example Problem
A school has 2,456 students. Each student needs 5 notebooks. How many notebooks are needed?
- Given: 2,456 students. 5 notebooks each.
- Operation: Multiplication.
- Estimate: 2,500 × 5 = 12,500
- Solve: 2,456 × 5 = 12,280 notebooks.
- Check: 12,280 ÷ 2,456 = 5. Correct.
Key Facts to Remember
- 'Addition and subtraction are INVERSE operations. Multiplication and division are INVERSE operations.'
- The product of any number and ZERO is ZERO.
- The quotient of any number divided by ONE is the number itself.
- Always ESTIMATE before solving — it helps you catch big mistakes.
- In BODMAS, division and multiplication have EQUAL priority (left to right).
Common Mistakes
| Mistake | Why It Is Wrong | Correct Approach |
|---|---|---|
| Subtracting a larger digit from a smaller without borrowing | 423 − 156: in tens column, 2 − 5 — you MUST borrow | Borrow 1 hundred: 12 tens − 5 tens = 7 tens |
| Forgetting the zero in partial products | 45 × 36: while multiplying by 30, write 1350 NOT 135 | The zero represents the ones place of 30 |
| BODMAS — adding before dividing | 12 ÷ 3 × 2 + 1 = ? Many solve 3 × 2 first | Division and multiplication have equal priority — go LEFT to RIGHT |
| Remainder larger than divisor | 17 ÷ 5 = 3 R 2 (not 2 R 7) | Remainder must ALWAYS be smaller than divisor |
Exam Focus (ICSE Class 5)
| Topic | Marks (Typical) | Question Type |
|---|---|---|
| Addition/Subtraction of large numbers | 4-5 marks | Direct computation |
| Multiplication and division | 4-5 marks | Word problems and computation |
| BODMAS | 3-4 marks | Simplify expressions |
| Word problems (multi-step) | 4-5 marks | Application-based |
| Properties of operations | 2-3 marks | Fill in the blanks / True-False |
Self-Test: 5 Questions
Q1. Simplify using BODMAS: 24 − [12 + (8 − 3) × 2] ÷ 6
Q2. A factory produces 1,245 toys per day. How many toys does it produce in 3 months (90 days)?
Q3. Find the product: 4,567 × 208
Q4. Divide and check: 8,945 ÷ 27
Q5. Riya has 500. She buys 3 books at 85 each and 2 pens at 12 each. How much money is left with her?
Answers
A1. 24 − [12 + (8 − 3) × 2] ÷ 6 = 24 − [12 + 5 × 2] ÷ 6 = 24 − [12 + 10] ÷ 6 = 24 − 22 ÷ 6 = 24 − 3.67 = 20.33
A2. 1,245 × 90 = 1,12,050 toys.
A3. 4,567 × 208 = 9,49,936.
A4. 8,945 ÷ 27 = 331 R 8. Check: 331 × 27 + 8 = 8,937 + 8 = 8,945.
A5. Spent = 3 × 85 + 2 × 12 = 255 + 24 = 279. Left = 500 − 279 = 221.
