Chapter 4 of 14

29%

Rajasthan (RBSE)Class 8 Mathematics★ 10-12 marks · CBSE Class 8 Maths (Ganita Prakash Chapter 4)

Quadrilaterals

"'Quadrilaterals' derives the properties of rectangles, squares, parallelograms, rhombuses, kites and trapeziums by geometric reasoning rather than assertion — using congruence and transversal arguments. Learn the Carpenter's Problem, the three equivalent definitions of a rectangle, how diagonal properties alone let you construct each shape, and how the whole family nests in a Venn diagram. CBSE Class 8 Maths (Ganita Prakash) Chapter 4."

⏱ 25 min readMedium difficulty✓ Free · NCERT-aligned

Worksheet

Podcast

Listen as a conversation

A teacher & a student talk through the chapter — in your language.

Mind Map

The chapter at a glance

Every concept and exam-favourite branch — revisable in 5 minutes.

…

Study Guide

Night-before notes

Key points, glossary and the questions most likely to show up.

…

VocabularyBuild your vocabularyLexiGenome mines the key words and schedules them with spaced repetition.Mine words →

By the end of this chapter you'll be able to…

1State the three equivalent definitions of a rectangle and explain why the shortest one (all angles 90°) is sufficient
2Prove that the diagonals of a rectangle are equal and bisect each other, using SAS and AAS congruence
3Show that the angle sum of any quadrilateral is 360° by splitting it into two triangles, including for a concave quadrilateral
4Derive the angle properties of a parallelogram from the transversal rules, and its side properties from congruence
5State and use the diagonal properties of rectangle, square, parallelogram, rhombus and kite, and construct each shape from its diagonals
6Distinguish a kite from a rhombus, and an isosceles trapezium from a parallelogram
7Place parallelograms, kites, rhombuses, rectangles and squares correctly in a Venn diagram
8Tell the difference between a conjecture reached by measurement and a property established by deduction

💡

Why this chapter matters

This is the chapter where geometry stops being a list of facts to memorise and becomes something you can *prove*. Every property here is derived — usually by spotting two congruent triangles — and the book is explicit that measuring a few figures gives only a conjecture, never certainty. The practical payoff is immediate: the Carpenter's Problem shows why crossing two equal sticks at their midpoints gives an exact right angle, a method carpenters in Europe and house-builders in Mozambique actually use.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

🔗

Congruence conditions for triangles — SSS, SAS, ASA, AAS (Class 7)

🔗

Angle sum of a triangle = 180°, and the isosceles triangle property

🔗

Transversal rules for parallel lines — alternate angles equal, co-interior angles supplementary

🔗

Compass-and-ruler construction of a perpendicular bisector

Quadrilaterals — Class 8 Mathematics (Ganita Prakash)

"Take any closed shape with four straight sides — its four angles always sum to 360°. From this single rule, the entire world of quadrilaterals unfolds."

What the book actually covers (2026-27) Ganita Prakash treats this chapter as an exercise in deduction, not memorisation. Every property is proved — usually by finding two congruent triangles, or by using the transversal rules for parallel lines — and the book repeatedly stresses the difference between a conjecture (noticed by measuring a few figures) and a proof (certain for all figures). Two consequences for what you are examined on. First, constructions here are driven by diagonal properties, not by the old "five cases" of 4-sides-and-a-diagonal — you are asked to construct a rectangle, parallelogram, rhombus, kite or square from its diagonals. Second, you are expected to justify, so an answer of "opposite angles are equal" earns little without the reason. The old five-case construction material is kept at the end of this page under Appendix — beyond the current syllabus; it is no longer part of this chapter.

1. About the Chapter

'Quadrilaterals' studies four-sided polygons — their types, properties, and construction. The word comes from the Latin quadri (four) and latus (side). After learning about triangles in Class 7, you now extend to richer shapes that fill the real world: walls, screens, kites, diamonds, parallelogram-shaped fields.

Key Idea

Every quadrilateral has 4 sides, 4 angles, and 2 diagonals. Its angle sum is always 360°.

The classification tree:

Quadrilateral
- Trapezium (one pair of parallel sides)
- Parallelogram (two pairs of parallel sides)
  - Rectangle (parallelogram + all 90° angles)
  - Rhombus (parallelogram + all sides equal)
    - Square (rectangle + rhombus)
- Kite (two pairs of adjacent sides equal)

2. Basic Properties of a Quadrilateral

Definition

A quadrilateral is a closed figure bounded by 4 straight line segments.

Components

4 sides (edges)
4 vertices (corners)
4 interior angles
2 diagonals (lines connecting opposite vertices)

The 360° Property (CRITICAL)

Sum of all interior angles of a quadrilateral = 360°.

Proof outline: Any quadrilateral can be divided into 2 triangles by a diagonal. Each triangle has angle sum 180°. So quadrilateral = 180° × 2 = 360°. ✓

Convex vs Concave

Convex quadrilateral: all interior angles < 180°
Concave quadrilateral: one interior angle > 180° (like a dart or arrowhead shape)

In Class 8 we mostly study convex quadrilaterals.

3. Types of Quadrilaterals — A Systematic Study

3.1 Trapezium (US: Trapezoid)

Definition: A quadrilateral with EXACTLY ONE pair of parallel sides.

Properties:

Only one pair of parallel sides (called bases)
The other two sides are NON-parallel
Isosceles trapezium: non-parallel sides are equal
Diagonals are equal in isosceles trapezium

Example: A simple ramp shape; a school bench profile.

3.2 Parallelogram

Definition: A quadrilateral with BOTH pairs of opposite sides parallel.

Properties (memorise all):

Opposite sides are equal (AB = CD; AD = BC)
Opposite sides are parallel (AB || CD; AD || BC)
Opposite angles are equal (∠A = ∠C; ∠B = ∠D)
Consecutive angles are supplementary (∠A + ∠B = 180°)
Diagonals bisect each other (the point where they cross divides each diagonal exactly in half)
Each diagonal divides the parallelogram into two congruent triangles

Example: A leaning bookshelf.

3.3 Rectangle

Definition: A parallelogram with ALL FOUR ANGLES equal to 90°.

Properties:

All properties of a parallelogram, PLUS:
All angles = 90°
Diagonals are EQUAL (AC = BD)
Diagonals bisect each other (from parallelogram property)

Example: A door, a TV screen, a book.

3.4 Rhombus

Definition: A parallelogram with ALL FOUR SIDES equal.

Properties:

All properties of a parallelogram, PLUS:
All sides equal (AB = BC = CD = DA)
Diagonals are PERPENDICULAR to each other (cross at 90°)
Diagonals bisect each other (from parallelogram)
Diagonals bisect the angles at vertices

Example: A traditional diamond shape on a playing card.

3.5 Square

Definition: A rectangle with all sides equal. (Equivalently: a rhombus with all angles 90°.)

Properties (all of rectangle AND rhombus):

All sides equal
All angles = 90°
Diagonals equal in length
Diagonals perpendicular
Diagonals bisect each other
Diagonals bisect vertex angles (so each angle becomes 45°)

Example: A chessboard square; a Rubik's cube face.

3.6 Kite

Definition: A quadrilateral with TWO PAIRS OF ADJACENT (consecutive) SIDES EQUAL.

Properties:

Two pairs of consecutive equal sides
One pair of opposite angles is equal (where the unequal sides meet)
Diagonals are perpendicular
One diagonal bisects the other

Example: An actual flying kite; certain gemstones.

4. The Quadrilateral Family Tree

            Quadrilateral
                 |
        ___________________
        |          |       |
   Trapezium  Kite  Parallelogram
                    |
              ____________
              |          |
          Rectangle  Rhombus
              |          |
              ___________
                   |
                Square

A square is at the bottom — it inherits properties from BOTH rectangle and rhombus.

5. Angle Sum and Exterior Angles

Interior Angle Sum

Sum = 360° for any quadrilateral.

If three angles are given, you can find the fourth: ∠D = 360° − (∠A + ∠B + ∠C).

Exterior Angle Sum

Sum of exterior angles (one at each vertex) of a quadrilateral = 360°.

In fact, sum of exterior angles of ANY polygon = 360°.

6. Diagonals — The Inner Lines

A quadrilateral has 2 diagonals (connecting opposite vertices).

Key facts:

Parallelogram: diagonals BISECT each other
Rectangle: diagonals are EQUAL in length
Rhombus: diagonals are PERPENDICULAR
Square: diagonals are EQUAL + PERPENDICULAR + bisect angles
Kite: diagonals are PERPENDICULAR (one bisects the other)
Isosceles trapezium: diagonals are EQUAL

7. The Carpenter's Problem — and Three Definitions of a Rectangle

The chapter opens its real work with a practical puzzle. A carpenter has two thin strips of wood. She wants to join them so that a thread passed round their four endpoints forms a rectangle. She already has one strip 8 cm long. How long must the other be, and where should they cross?

Modelled geometrically, the strips are the diagonals of the quadrilateral their endpoints form. So three questions have to be answered.

Deduction 1 — How long is the other diagonal?

In rectangle ABCD, compare △ADC and △DAB: AB = CD (opposite sides), ∠BAD = ∠CDA = 90°, and AD is common. So △ADC ≅ △DAB by SAS, giving AC = BD.

The diagonals of a rectangle are equal. The second strip must also be 8 cm.

Deduction 2 — Where do they cross?

Compare △AOB and △COD. The vertically opposite angles at O are equal. For ∠1 and ∠2: since ∠B = 90°, ∠3 + ∠1 = 90°; and in △BCD, ∠3 + ∠2 + 90° = 180°, so ∠3 + ∠2 = 90°. Hence ∠1 = ∠2 = 90° − ∠3. By AAS, △AOB ≅ △COD, so OA = OC and OB = OD.

The diagonals of a rectangle bisect each other. The strips must be joined at their midpoints.

Deduction 3 — At what angle?

At any angle. Let the angle between the diagonals be x. The four angles at O are x, x, 180° − x, 180° − x. Each of the four triangles round O is isosceles, so its base angles are

$a = \frac{180 - x}{2} = 90 - \frac{x}{2}, b = \frac{x}{2}$

Each corner of the quadrilateral is one a plus one b:

$(90 - \frac{x}{2}) + \frac{x}{2} = 90°$

Whatever the angle between them, equal diagonals that bisect each other always give a rectangle.

This is not just a textbook result. Carpenters in Europe square up frames this way, and farmers in Mozambique use it to lay out a rectangular house base — no protractor needed.

The three definitions, all equivalent

The chapter shows that each of these picks out exactly the same set of shapes:

A quadrilateral whose angles are all 90° and whose opposite sides are equal.
A quadrilateral whose diagonals are equal and bisect each other.
A quadrilateral in which all the angles are 90° — the shortest of the three.

Why does definition 3 suffice? Deduction 4: in a quadrilateral with all angles 90°, join BD; the same ∠1 = ∠2 argument gives △BAD ≅ △DCB by AAS, so AD = CB and DC = BA. All-right-angles forces opposite sides to be equal, so nothing is lost by dropping that clause.

And for a square

Deduction 5: if the diagonals are equal, bisect each other and meet at 90°, then △BOA ≅ △BOC by SSS, so ∠BOA = ∠BOC; being a linear pair they are 90° each.

The diagonals of a square are equal, bisect each other at right angles, and bisect the angles of the square.

Conjecture versus proof

The book is emphatic on this point. Constructing a few rectangles and measuring their diagonals shows the property seems to hold — that is a conjecture. But can you be sure the 1000th rectangle behaves the same? Only a deduction like the ones above settles it. Measure to get insight; prove to be certain.

7A. Constructing from Diagonal Properties

This is how the chapter asks you to construct, and how you will be examined.

Shape	Diagonals are…	Construction
Rectangle	equal, bisect each other	Draw one diagonal, bisect it at O, draw the second through O at any angle with equal halves
Square	equal, bisect each other at 90°	Same, but erect the second diagonal perpendicular at O (compass, no protractor)
Parallelogram	bisect each other (need not be equal)	Draw one diagonal, bisect at O, draw the second through O at the given angle with equal halves
Rhombus	bisect each other at 90° (need not be equal)	Draw one diagonal, bisect at O, erect a perpendicular, mark equal halves of the second
Kite	one bisects the other at 90°	Draw one diagonal, construct its perpendicular bisector, mark the second diagonal's ends on it with an unequal split

Notice the pattern: "equal" controls the angles of the shape, and "perpendicular" controls the sides.

8. Worked Examples

Example 1: Find Missing Angle

A quadrilateral has angles 70°, 110°, 80°. Find the fourth angle.

Sum = 360°.
4th angle = 360° − (70° + 110° + 80°) = 360° − 260° = 100° ✓

Example 2: Parallelogram Properties

In parallelogram ABCD, ∠A = 65°. Find ∠B, ∠C, ∠D.

∠C = 65° (opposite angles equal)
∠B = ∠D = 180° − 65° = 115° (consecutive angles supplementary)

Example 3: Rectangle Diagonal

In rectangle ABCD with AB = 6 cm, BC = 8 cm, find AC.

Using Pythagoras (because ∠B = 90°):
AC² = AB² + BC² = 36 + 64 = 100
AC = 10 cm

Example 4: Rhombus Diagonal

A rhombus has diagonals 12 cm and 16 cm. Find the side.

Diagonals bisect at 90° in a rhombus
Half-diagonals: 6 cm and 8 cm
Side = √(6² + 8²) = √100 = 10 cm

Example 5: Trapezium Angles

In a trapezium ABCD, AB || CD, ∠A = 50°. Find ∠D.

Co-interior angles (since AB || CD): ∠A + ∠D = 180°
∠D = 180° − 50° = 130°

Example 6: Identify Quadrilateral

ABCD has AB = CD = 5 cm, BC = AD = 5 cm, and ∠A = 90°. Identify it.

All four sides equal → could be square or rhombus
∠A = 90° → square (in a rhombus, angles vary)
Answer: Square

9. Common Mistakes

Confusing trapezium with parallelogram
- Trapezium: ONE pair parallel
- Parallelogram: BOTH pairs parallel
Forgetting that square is BOTH rectangle and rhombus
- A square has all properties of both
Wrong angle assumptions
- Don't assume angles are 90° unless told
- Don't assume sides are equal unless told
Diagonals confusion
- Parallelogram: bisect each other (but NOT equal, NOT perpendicular in general)
- Rectangle: equal + bisect (NOT perpendicular)
- Rhombus: perpendicular + bisect (NOT equal)
- Square: ALL properties
Construction without 5 measurements
- You need 5 measurements (in proper combinations) to UNIQUELY determine a quadrilateral

10. Special Properties Worth Remembering

Pythagoras in Quadrilaterals

Many problems use the Pythagoras theorem (which you'll formally study in Chapter 9):

Rectangle diagonal: d = √(L² + B²)
Square diagonal: d = a√2 (where a = side)
Rhombus side from diagonals: s = √((d₁/2)² + (d₂/2)²)

Area Formulas (Preview for Chapter 14)

Square: a²
Rectangle: L × B
Parallelogram: base × height
Rhombus: (1/2) × d₁ × d₂
Trapezium: (1/2) × (sum of parallel sides) × height
Kite: (1/2) × d₁ × d₂

Perimeter Formulas

Rectangle: 2(L + B)
Square: 4a
Rhombus: 4a (all sides equal)
General quadrilateral: sum of all sides

11. Quadrilaterals Around You

Architecture

Most rooms, walls, doors, windows are rectangles
Floor tiles often square
Some traditional motifs use rhombuses and kites

Art

Cubist art (Picasso) uses quadrilateral shapes
Indian temple architecture has many quadrilateral patterns

Nature

Honeycomb cells are HEXAGONS, but some crystals are quadrilateral
Many salt crystals are cubic (square faces)

Sports

Cricket pitch, football field, hockey field — all rectangles
Carom board — square
Kabaddi court — rectangle

Vehicles

Truck bodies, train coaches — rectangular sides
Aircraft wings often trapezoidal

12. Tips for Mastery

For Identification

Memorise the PROPERTIES of each type
Use the FAMILY TREE to know inheritance (square = rectangle + rhombus)

For Properties Application

Apply properties step by step
Use the 360° rule for missing angles

For Construction

Draw NEATLY using ruler, compass, protractor
Use light pencil first; darken only after verifying

For Problem-Solving

Identify the type of quadrilateral first
Then apply specific properties
Verify your answer (e.g., angle sum = 360°)

13. Historical Context

Ancient Indian Geometry

Sulba Sutras had detailed quadrilateral constructions for fire altars
Quadrilateral 'vedis' (altars) had specific dimensions

Greek Contribution

Euclid (~300 BCE) systematised quadrilateral geometry in 'Elements'
Theorems on parallelograms come from Euclid

Modern Use

Quadrilateral mesh in computer graphics
Image processing uses quadrilateral patches
GPS triangulation uses quadrilateral coordinate systems

14. Conclusion

Quadrilaterals are everywhere — in architecture, design, art, and daily life. Mastering their properties is essential for:

Later geometry (Class 9 onwards)
Trigonometry (Class 10 onwards)
Coordinate geometry (Class 9 onwards)
3D shapes (later chapters)

The single principle — angle sum = 360° — combined with the family-tree of types and their properties, gives you a complete toolkit for any quadrilateral problem.

Practice constructions with rigour, memorise properties precisely, and you'll find that the world around you is more geometric than you ever realised.

15. Hands-On Activities in the Book

These are examinable in spirit — they are how the chapter expects you to discover results before proving them.

Geoboard

Place two rubber bands of equal length perpendicular to each other so they bisect one another, and join the ends. You get a square. Now extend one band by 2 cm on each side and rejoin: the diagonals are still perpendicular and still bisect each other, but are no longer equal — so you now get a rhombus.

Joining two triangles

Triangles joined along a full equal side	Result
Two equilateral triangles, side 8 cm	Rhombus (all sides 8 cm; angles 60°, 120°, 60°, 120°)
Two isosceles triangles 8, 8, 6 cm — joined along the 6 cm side	Rhombus (all sides 8 cm)
The same two joined along an 8 cm side	Kite (sides 8, 6, 8, 6 arranged in adjacent pairs)
Two scalene triangles 6, 9, 12 cm — joined along matching sides	Parallelogram or kite, depending on which side is glued

Joining a scalene pair along the 12 cm sides in the "flipped" orientation is exactly how the book introduces the kite: sides 6, 9, 9, 6 in adjacent equal pairs.

Which Quad? (paper folding)

Fold a sheet in half, then into a quarter, then make a triangular crease at the corner sitting at the middle of the paper. Open it out and identify the shape the creases form. The book then asks you to reproduce given crease patterns, and to find the fold that produces a square.

16. Kite and Trapezium — the Book's Definitions

Kite: a quadrilateral that can be labelled ABCD so that AB = BC and CD = DA — two non-overlapping adjacent pairs of equal sides.

Its key property: the diagonal BD bisects ∠ABC and ∠ADC, and bisects AC at right angles (from △AOB ≅ △COB). Note the asymmetry — only one diagonal is bisected. That is precisely what separates a kite from a rhombus.

Trapezium: a quadrilateral with at least one pair of parallel opposite sides. In trapezium PQRS with PQ ∥ SR, the co-interior rule gives ∠S + ∠P = 180° and ∠R + ∠Q = 180°.

Isosceles trapezium: a trapezium whose non-parallel sides are equal. Dropping perpendiculars XY and WZ from the shorter parallel side onto the longer one creates a rectangle in the middle plus two congruent right triangles at the ends, which forces the angles opposite the equal sides to be equal (∠U = ∠V).

An isosceles trapezium is not a parallelogram — only one pair of its sides is parallel.

Appendix — beyond the current syllabus

The five-case construction method below belonged to the old Class 8 chapter on Practical Geometry. Ganita Prakash does not teach it — its constructions come from diagonal properties instead (see section 7A). It is kept here because the compass-and-arc technique remains useful, and because some school worksheets still circulate these cases.

Constructing a quadrilateral from 5 measurements

To pin down a general quadrilateral uniquely you need 5 independent measurements, in one of these combinations:

Case 1 — 4 sides + 1 diagonal. Given AB, BC, CD, DA and AC:

Draw AC to the given length.
With centre A and radius AB, draw an arc.
With centre C and radius BC, draw an arc; their intersection is B.
With centre A and radius AD, draw an arc on the other side of AC.
With centre C and radius CD, draw an arc; their intersection is D.
Join AB, BC, CD and DA.

Case 2 — 3 sides + 2 diagonals. Given AB, BC, CD and both AC, BD.

Case 3 — 2 adjacent sides + 3 angles. Given AB, BC and ∠A, ∠B, ∠C.

Case 4 — 3 sides + 2 included angles. Given AB, BC, CD and ∠B, ∠C.

Case 5 — special types need fewer measurements.

Shape	Minimum data
Square	one side
Rectangle	two adjacent sides
Rhombus	one side + one diagonal (or one side + one angle)
Parallelogram	two adjacent sides + the included angle

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Angle sum of a quadrilateral

∠A + ∠B + ∠C + ∠D = 360°

Proved by splitting into two triangles; holds for concave quadrilaterals too, with the reflex angle counted.

Angles when diagonals meet at x

base angles = 90 − x/2 and x/2, each corner = 90°

Why equal diagonals bisecting each other always give a rectangle, whatever x is.

Parallelogram angles

opposite equal; adjacent add to 180°

Adjacent angles are co-interior angles on a transversal.

Rhombus diagonals

bisect each other at 90°, and bisect the angles

Not necessarily equal — that is what separates a rhombus from a square.

Kite diagonal

BD bisects AC at 90°, and bisects ∠ABC and ∠ADC

Only ONE diagonal is bisected — the asymmetry that separates a kite from a rhombus.

Square from midpoints

side = x√2 when outer side is 2x

Joining midpoints of a square gives a square of exactly half the area.

⚠️

Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT

✗ Treating a property of a shape as a definition of it

✓ A definition must exclude everything outside the class. Test any proposed definition by trying to build a counter-example.

WATCH OUT

✗ Thinking perpendicular diagonals make a rhombus

✓ A rhombus needs the diagonals to bisect EACH OTHER at 90°. In a kite only one diagonal bisects the other.

WATCH OUT

✗ Thinking equal diagonals that bisect each other make a square

✓ A square needs the diagonals to be equal, bisect each other AND meet at 90°. 'Equal' controls the angles; 'perpendicular' controls the sides.

WATCH OUT

✗ Calling an isosceles trapezium a parallelogram

✓ A trapezium has AT LEAST one pair of parallel sides; a parallelogram needs both pairs.

WATCH OUT

✗ Getting the angle sum wrong on a concave quadrilateral

✓ The sum is still 360°. Draw the diagonal that lies inside the figure, and measure the reflex angle at the dented vertex.

WATCH OUT

✗ Using the old five-case construction method (4 sides + 1 diagonal, etc.)

✓ Learn the diagonal recipe for each shape. It has been moved to an appendix on the chapter page for reference.

WATCH OUT

✗ Writing a property with no justification

✓ Name the congruence condition (SSS/SAS/ASA/AAS) or the transversal rule you used. Most marks sit in the reason, not the answer.

NCERT exercises (with solutions)

Every NCERT exercise from this chapter — what it covers and how many questions to expect.

Figure it Out — Rectangles and Squares

Questions

Figure it Out — Parallelograms and Rhombuses

Questions

Figure it Out — Kites, Trapeziums and Relationships Between Quadrilaterals

Questions

Practice problems

Work through this chapter's problems as a readiness check — reveal each solution, mark yourself honestly, and get your gap report at the end.

Readiness check

Are you exam-ready for Quadrilaterals?

8 problems from this chapter. Try each one, reveal the worked solution, mark yourself honestly — get your gap report at the end.

8 questions~6 min worth ~12 marks in Rajasthan (RBSE) exams

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

•Rectangle: all angles 90°. Equivalently, diagonals equal and bisecting each other.
•Square: all angles 90° and all sides equal. Diagonals equal, bisect each other at 90°, and bisect the angles.
•Parallelogram: opposite sides parallel. Opposite sides and opposite angles equal; adjacent angles supplementary; diagonals bisect each other but need not be equal.
•Rhombus: all sides equal. It is a parallelogram, so it inherits all the above; additionally its diagonals meet at 90° and bisect the angles.
•Kite: AB = BC and CD = DA. Diagonal BD bisects AC at right angles and bisects ∠ABC and ∠ADC — but AC does not bisect BD.
•Trapezium: at least one pair of parallel sides. Co-interior angles on each non-parallel side add to 180°.
•Isosceles trapezium: non-parallel sides equal, so the angles opposite them are equal. NOT a parallelogram.
•Angle sum of any quadrilateral is 360°, proved by splitting into two triangles — true for concave shapes too.
•A quadrilateral with three right angles must have a fourth, so exactly three right angles is impossible.
•Nesting: square ⊂ rectangle ⊂ parallelogram, square ⊂ rhombus ⊂ parallelogram, and rhombus ⊂ kite.
•Construction is from diagonal properties: 'equal' fixes the angles, 'perpendicular' fixes the sides.

Rajasthan (RBSE) marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 10-12 marks per chapter

Question type	Marks each	Typical count	What it tests
MCQ / Very Short	1	2-3	Identification; properties; angle sum
Short Answer	2-3	2	Property application; diagonal calculations
Long Answer	5	1	Construction; multi-step properties; word problems

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Carpenters in Europe square up a rectangular frame by cro…

Carpenters in Europe square up a rectangular frame by crossing two equal battens at their midpoints — the Carpenter's Problem exactly

Farmers in Mozambique lay out a rectangular house base wi…

Farmers in Mozambique lay out a rectangular house base with the same two-strings-and-a-cord method, no protractor needed

Screens

Screens, doors, windows, tiles and picture frames are all checked for square by measuring whether the two diagonals are equal

Kite-making relies on the perpendicular-diagonal property…

Kite-making relies on the perpendicular-diagonal property to keep the frame rigid and symmetric

Parallelogram linkages in car jacks

Parallelogram linkages in car jacks, folding gates and drawing pantographs keep opposite bars parallel while the shape flexes

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

Three question types dominate. (1) Angle chases — a diagonal or an intersection angle is given and you must find the rest. Always start by naming the property that makes a triangle isosceles (OA = OB from bisecting diagonals, or two equal sides), then use the 180° triangle sum; finish by checking the four angles total 360°. (2) Construction from diagonals — state which diagonal property you are using before you draw, and check your figure by measuring a side against the value you can compute with Pythagoras. (3) True/false and 'justify' questions — these carry most of the marks in the reason, so name the congruence condition or transversal rule, and for a false statement always give a concrete counter-example (kite for perpendicular diagonals, non-square rectangle for equal diagonals). Do NOT use the old five-case construction method; it is not in this book.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 8 School ExamVery High

Class 8 Maths Olympiad (IMO)High

NTSE Mental AbilityMedium

Class 9 QuadrilateralsVery High — direct continuation

Geometry OlympiadsHigh

AI helpers for this chapter

Generate more practice on the fly, or have the chapter explained at a different level.

⚡

Generate 5 more questions

Fresh MCQs + short-answer items based on this chapter, plus answer keys.

🧠

Explain at a different level

Re-explain the chapter at the level you actually want.

📝 My notes

Saved on this device — sign in to sync · how this works

0/600

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

No. That was the old Practical Geometry chapter. Ganita Prakash constructs every special quadrilateral from its diagonal properties instead — you will be asked to construct a rhombus from its two diagonals, for example. The old method is kept in an appendix on the chapter page for reference only.

Under the definition Ganita Prakash gives — a quadrilateral labelled ABCD with AB = BC and CD = DA — yes, a square satisfies it, and the book's own Venn diagram places the square inside the kite region. Be aware the printed answer key contradicts itself on this point in the page-107 exercise; the chapter's solutions page explains exactly where.

The four angles must total 360°. If three are 90° they account for 270°, leaving exactly 90° for the fourth. So three right angles automatically force a fourth — and the shape is a rectangle.

Constructing a few rectangles and measuring shows the diagonals appear to bisect each other — that is a conjecture, a statement you are confident about. A proof, like the AAS argument in Deduction 2, shows it must hold for every rectangle including the ones you never draw. The book asks for deduction whenever the question says 'justify' or 'using geometric reasoning'.

Two words. 'Equal' diagonals control the ANGLES — equal + bisecting gives all angles 90°, a rectangle. 'Perpendicular' diagonals control the SIDES — perpendicular + bisecting gives all sides equal, a rhombus. Both together give a square.

Practice more, ask doubts, find a tutor

Rajasthan (RBSE) Class 8 mock tests

Rajasthan (RBSE) Class 8 PYQs

Ask in Q&A

Mathematics flashcards

Related chapters

Students who read Quadrilaterals usually read these next.

A Square and A Cube

'A Square and A Cube' opens NCERT Class 8 Mathematics (Ganita Prakash) — exploring perfect squares, square roots, perfect cubes, and cube roots through visual patterns, historical context, and hands-on activities. Master squares up to 50², cubes up to 30³, prime factorisation methods, and the geometric meaning of "squaring" and "cubing". CBSE Class 8 Maths Chapter 1.

Power Play

'Power Play' explores exponents and powers — how to write enormous or microscopic numbers compactly using the language of bases and exponents. Master laws of exponents, negative exponents, fractional exponents, scientific notation, and the elegant way mathematics handles numbers as large as the universe and as small as an atom. CBSE Class 8 Maths (Ganita Prakash) Chapter 2.

A Story of Numbers

"'A Story of Numbers' traces how humans learned to write numbers — from tally marks on bone and Gumulgal counting in twos, through Roman and Egyptian numerals, to the base-5, Mesopotamian base-60 and Mayan systems, and finally to the Hindu place value system with zero. Learn what landmark numbers and a base are, why place value needs a zero, and why this made calculation possible. CBSE Class 8 Maths (Ganita Prakash) Chapter 3."

Number Play

"'Number Play' is about divisibility reasoning — not just the tests but WHY they work. Learn to add and subtract remainders directly, solve 'always/sometimes/never true' claims with algebra, master the digital root and its link to division by 9, combine coprime tests for divisors like 18, 36 and 44, and crack cryptarithms by reasoning from the units column. CBSE Class 8 Maths (Ganita Prakash) Chapter 5."

🧑‍🏫