By the end of this chapter you'll be able to…

  • 1Define the circle and its parts: radius, chord, diameter, arc, secant, tangent, sector, segment
  • 2Describe the line and rotational symmetry of a circle
  • 3State and use the chord properties (perpendicular from centre bisects a chord; equal chords equidistant)
  • 4Apply r² = d² + ℓ² to relate radius, centre-distance and chord length
  • 5Explain why exactly one circle passes through three non-collinear points and construct it
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Why this chapter matters
Circle properties are pure-geometry favourites in the RBSE paper — chord theorems and the 'distance–radius–half-chord' Pythagoras link give reliable 2–3 mark questions, and the constructions (circle through three points) test reasoning. It is the foundation for the Class 10 Circles (tangents) chapter.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Circles — Symmetry, Chords and Constructions (RBSE Class 9 · Mathematics)

The circle is the most symmetric shape there is — turn it any amount about its centre and it looks unchanged. The new book captures that with a playful title, "I'm Up and Down, and Round and Round." This chapter turns that symmetry into precise, provable facts about chords and constructions.

RBSE note (2026-27). Class 9 uses the new NCF (Ganita Prakash 9) Mathematics textbook; this chapter's book title is "I'm Up and Down, and Round and Round." BSER (Ajmer) sets the exam.


1. Circle vocabulary

A circle is the set of all points in a plane at a fixed distance (the radius) from a fixed point (the centre).

TermMeaning
Radius (r)centre to any point on the circle
Chorda segment joining two points on the circle
Diameter (d)the longest chord; passes through the centre; d = 2r
Arca part of the circle (minor / major)
Secanta line cutting the circle at two points
Tangenta line touching the circle at one point
Sectorregion between two radii and an arc
Segmentregion between a chord and an arc

The interior + the circle + the exterior partition the plane.


2. Symmetries of a circle

  • Line (reflective) symmetry: every line through the centre is a line of symmetry — a circle has infinitely many.
  • Rotational symmetry: a circle maps onto itself under any angle of rotation about its centre (infinite-order rotational symmetry).

This symmetry is the reason behind every chord theorem below.


3. Chord properties (provable from symmetry)

  1. The perpendicular from the centre to a chord bisects the chord. (And conversely, the line from the centre to the midpoint of a chord is perpendicular to it.)

  2. The perpendicular bisector of a chord passes through the centre. — This is how you find an unknown centre.

  3. Equal chords are equidistant from the centre (and chords equidistant from the centre are equal).

If a chord of length is at distance from the centre of a circle of radius , then by Pythagoras:


4. How many circles pass through given points?

  • Through one point: infinitely many circles.
  • Through two points A and B: infinitely many — all their centres lie on the perpendicular bisector of AB.
  • Through three non-collinear points: exactly one circle. Its centre is where the perpendicular bisectors of two of the chords meet (this is the circumcentre).
  • Through three collinear points: no circle.

This gives a construction: to draw the unique circle through three points, draw the perpendicular bisectors of two pairs; their intersection is the centre, and its distance to any of the points is the radius.


5. Worked example

A chord of a circle of radius 5 cm is at a distance of 3 cm from the centre. Find the length of the chord.

Half-chord : .

Chord length 8 cm.


6. Quick recap

  • A circle = points at fixed distance r from the centre; diameter d = 2r is the longest chord.
  • Know chord, arc, secant, tangent, sector, segment.
  • A circle has infinitely many lines of symmetry (all through the centre) and infinite rotational symmetry.
  • Perpendicular from centre bisects a chord; the perpendicular bisector of a chord passes through the centre; equal chords are equidistant from the centre.
  • Use to link radius, centre-distance and half-chord.
  • Exactly one circle passes through three non-collinear points (centre = circumcentre).

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Diameter
d = 2r
Longest chord; passes through the centre.
Chord–distance relation
r² = d² + ℓ²
d = centre-to-chord distance, ℓ = half the chord length.
Chord length
chord = 2ℓ = 2√(r² − d²)
From the relation above.
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Using the full chord instead of half in r² = d² + ℓ²
ℓ is HALF the chord, because the perpendicular from the centre bisects it. Chord length = 2ℓ.
WATCH OUT
Thinking a chord and a diameter are different kinds of things
A diameter IS a chord — the special longest one that passes through the centre.
WATCH OUT
Saying a circle has 4 lines of symmetry
A circle has INFINITELY many lines of symmetry — every line through the centre.
WATCH OUT
Believing a circle can pass through any three points
Only three NON-collinear points give a (unique) circle. Three collinear points give none.
WATCH OUT
Forgetting the perpendicular bisector of a chord passes through the centre
This is the key fact used to locate an unknown centre — draw two and intersect them.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Vocabulary
What is the longest chord of a circle called?
Show solution
The diameter (it passes through the centre and equals 2r). ✦ Answer: the diameter.
Q2EASY· Symmetry
How many lines of symmetry does a circle have?
Show solution
Infinitely many — every line through the centre. ✦ Answer: infinitely many.
Q3EASY· Diameter
A circle has radius 7 cm. What is its diameter?
Show solution
d = 2r = 2 × 7 = 14 cm. ✦ Answer: 14 cm.
Q4MEDIUM· Chord
A chord of length 24 cm is drawn in a circle of radius 13 cm. How far is it from the centre?
Show solution
Step 1 — half-chord ℓ = 12 cm. Step 2 — r² = d² + ℓ² → 13² = d² + 12² → 169 = d² + 144. Step 3 — d² = 25 → d = 5 cm. ✦ Answer: 5 cm.
Q5MEDIUM· Chord
A chord is 8 cm from the centre of a circle of radius 10 cm. Find the chord's length.
Show solution
Step 1 — ℓ² = r² − d² = 100 − 64 = 36 → ℓ = 6. Step 2 — chord = 2ℓ = 12 cm. ✦ Answer: 12 cm.
Q6MEDIUM· Property
State the property used to locate the centre of a circle from a chord.
Show solution
The perpendicular bisector of any chord passes through the centre. Drawing the perpendicular bisectors of two chords; their intersection is the centre. ✦ Answer: perpendicular bisector of a chord passes through the centre.
Q7HARD· How many circles
How many circles pass through three given points? Explain for non-collinear and collinear cases.
Show solution
Step 1 — Three NON-collinear points: exactly ONE circle; its centre is the intersection of the perpendicular bisectors of two of the chords (the circumcentre). Step 2 — Three COLLINEAR points: the perpendicular bisectors are parallel and never meet, so NO circle passes through them. ✦ Answer: one (non-collinear); none (collinear).
Q8HARD· Equal chords
Two equal chords of a circle of radius 17 cm are each 15 cm long. Show they are equidistant from the centre and find that distance.
Show solution
Step 1 — Equal chords are equidistant from the centre (chord theorem), so both have the same d. Step 2 — ℓ = 15/2 = 7.5 cm; d² = r² − ℓ² = 289 − 56.25 = 232.75. Step 3 — d = √232.75 ≈ 15.26 cm. ✦ Answer: equidistant; d ≈ 15.26 cm.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Circle = points at distance r from the centre; diameter d = 2r is the longest chord.
  • Parts: chord, arc, secant, tangent, sector, segment.
  • Symmetry: infinitely many lines of symmetry (through the centre) and infinite rotational symmetry.
  • Perpendicular from the centre bisects a chord; perpendicular bisector of a chord passes through the centre.
  • Equal chords are equidistant from the centre (and vice versa).
  • r² = d² + ℓ² (ℓ = half-chord); chord = 2√(r² − d²).
  • Exactly one circle through three non-collinear points (circumcentre); none if collinear.

Rajasthan (RBSE) marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 5–7 marks

Question typeMarks eachTypical countWhat it tests
MCQ / fill in the blank11–2Vocabulary, symmetry, diameter
Short answer / numerical22Chord–distance with r² = d² + ℓ²; properties
Short answer + proof/construction31How-many-circles reasoning; equal chords; construction
Prep strategy
  • Memorise the chord theorems and the r² = d² + ℓ² relation
  • Always halve the chord before using Pythagoras
  • Practise the 'circle through three points' construction and reasoning
  • Draw a neat figure for every chord/centre question

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Finding a wheel's centre

Workshops use the perpendicular-bisector-of-a-chord trick to locate the exact centre of a disc.

Architecture & arches

Circular arcs and their chords are designed using these exact relations.

GPS trilateration

Locating a point as the intersection of circles of known radius is the circumcircle idea in action.

Design & manufacturing

Symmetry of the circle underlies gears, lenses and turntables.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Draw the figure and drop the perpendicular from the centre to the chord first.
  2. Use r² = d² + ℓ² with ℓ = half the chord; never the full chord.
  3. For 'how many circles', argue via perpendicular bisectors of chords.
  4. Quote the chord theorem you use as the first line of a proof.
  5. State units and keep the figure labelled for method marks.

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Angle subtended by a chord at the centre vs on the circle (Class 10 preview).
  • Cyclic quadrilaterals and the circumcircle of a triangle.
  • Power of a point and intersecting-chords theorem.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

RBSE Class 9 Annual (BSER Ajmer)High — chord numericals + a proof each year
NTSE / NMMSMedium — circle-property MCQs
JEE FoundationHigh — base for Class 10 Circles (tangents)
Maths Olympiad (IMO)Medium-high — circle geometry is a staple

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

It is a playful nod to a circle's perfect symmetry — it looks the same however you flip it (up/down) or turn it (round and round). The maths content is standard circle geometry.

Yes — a diameter is the longest chord, the one that passes through the centre. Every diameter is a chord, but not every chord is a diameter.

Because the perpendicular from the centre bisects the chord, the right triangle has legs d (centre to chord) and ℓ (half the chord), with the radius r as hypotenuse.

Draw any two chords, construct their perpendicular bisectors, and where the bisectors meet is the centre (both bisectors pass through it).
Verified by the tuition.in editorial team
Last reviewed on 15 June 2026. Written and reviewed by subject-matter experts — read about our process.
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