Numbers and Sequences — Class 10 Maths (Samacheer Kalvi)
TN State Board (Samacheer Kalvi) Class 10 Mathematics, Chapter 2. Number theory basics and the arithmetic of sequences.
1. About this chapter
This chapter covers Euclid's division lemma and algorithm, the fundamental theorem of arithmetic, modular arithmetic, arithmetic (AP) and geometric (GP) progressions, and special series.
2. Number theory
- Euclid's division lemma: for positive integers a, b there exist unique q, r with a = bq + r, 0 ≤ r < b.
- Euclid's division algorithm: repeated use of the lemma gives the HCF of two numbers.
- Fundamental theorem of arithmetic: every composite number can be written as a unique product of primes (apart from order).
- Modular arithmetic: working with remainders (a ≡ b (mod n)).
3. Arithmetic progression (AP)
- General form: a, a + d, a + 2d, … with common difference d.
- nth term: tₙ = a + (n − 1)d.
- Sum of n terms: Sₙ = n/2 [2a + (n − 1)d] = n/2 (a + l) (l = last term).
4. Geometric progression (GP) and special series
- General form: a, ar, ar², … with common ratio r.
- nth term: tₙ = a r^(n−1).
- Sum of n terms: Sₙ = a(rⁿ − 1)/(r − 1) (r ≠ 1).
- Special series: Σn = n(n+1)/2; Σn² = n(n+1)(2n+1)/6; Σn³ = [n(n+1)/2]².
5. Worked examples
Example 1. Find the HCF of 24 and 36 using Euclid's algorithm. 36 = 24×1 + 12; 24 = 12×2 + 0 → HCF = 12.
Example 2. Find the 10th term of the AP 3, 7, 11, … a = 3, d = 4; t₁₀ = a + 9d = 3 + 36 = 39.
Example 3. Find the sum of the first 20 natural numbers. Σn = n(n+1)/2 = 20×21/2 = 210.
Example 4. Find the sum of the GP 2 + 6 + 18 + … to 5 terms. a = 2, r = 3; S₅ = 2(3⁵ − 1)/(3 − 1) = 2(243 − 1)/2 = 242.
6. Common mistakes
- Mistake: Using r = 1 in the GP sum formula. Fix: If r = 1, Sₙ = na (the formula needs r ≠ 1).
- Mistake: Forgetting (n − 1) in the nth-term formulas. Fix: AP tₙ = a + (n − 1)d; GP tₙ = a r^(n − 1).
- Mistake: Confusing common difference and common ratio. Fix: AP has a common difference; GP has a common ratio.
7. Practice (book-back style)
- State Euclid's division lemma.
- Find the 15th term of the AP 5, 8, 11, …
- Find the sum of the first 12 terms of the AP 2, 5, 8, …
- Find the 6th term of the GP 3, 6, 12, …
- Find Σn² for n = 10.
8. Answer key
- a = bq + r with 0 ≤ r < b, for positive integers a and b.
- a = 5, d = 3; t₁₅ = 5 + 14×3 = 47.
- S₁₂ = 12/2[2(2) + 11(3)] = 6[4 + 33] = 6×37 = 222.
- a = 3, r = 2; t₆ = 3×2⁵ = 96.
- Σn² = 10×11×21/6 = 385.
9. Quick revision
- Chapter 2 · number theory + AP/GP + special series.
- Euclid: a = bq + r; algorithm → HCF; FTA → unique prime factorisation.
- AP: tₙ = a + (n−1)d; Sₙ = n/2[2a + (n−1)d].
- GP: tₙ = a r^(n−1); Sₙ = a(rⁿ − 1)/(r − 1).
- Σn = n(n+1)/2; Σn² = n(n+1)(2n+1)/6; Σn³ = [n(n+1)/2]².
