By the end of this chapter you'll be able to…

  • 1State and apply Newton's three laws of motion
  • 2Calculate momentum, force and impulse
  • 3Apply the law of conservation of linear momentum
  • 4Use Newton's universal law of gravitation and g = GM/R²
  • 5Distinguish mass from weight and find apparent weight
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Why this chapter matters
Laws of Motion is the foundation of mechanics. It explains how forces change motion through Newton's laws, momentum and impulse, and introduces gravitation — concepts essential for the TN SSLC exam and for higher physics.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Laws of Motion — Class 10 Science (Samacheer Kalvi)

TN State Board (Samacheer Kalvi) Class 10 Science, Physics — Chapter 1. The foundation of mechanics: how forces change motion, momentum, and gravitation.


1. About this chapter

This chapter explains why and how objects move when forces act on them. It builds on Newton's three laws, introduces momentum and impulse, states the law of conservation of linear momentum, and ends with Newton's universal law of gravitation and the difference between mass and weight.

2. Newton's laws of motion

  • First law (law of inertia): A body continues in its state of rest or uniform motion in a straight line unless acted upon by an external force. Inertia is the resistance of a body to a change in its state; types — inertia of rest, of motion, of direction.
  • Second law: The rate of change of momentum is proportional to the applied force and acts in the direction of the force. This gives F = ma.
  • Third law: Every action has an equal and opposite reaction (forces act on different bodies).

3. Key terms and formulas

QuantityFormulaUnit
Linear momentump = m vkg m s⁻¹
ForceF = m a = Δp / Δtnewton (N)
ImpulseJ = F × t = ΔpN s
Conservation of momentumm₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Universal gravitationF = G m₁m₂ / r²(G = 6.674×10⁻¹¹ N m² kg⁻²)
Acceleration due to gravityg = G M / R²≈ 9.8 m s⁻²
WeightW = m gnewton (N)
  • Impulse = large force acting for a short time; equals the change in momentum.
  • Law of conservation of linear momentum: in the absence of external force, the total momentum of a system is constant (basis of rocket propulsion and recoil of a gun).

4. Mass and weight

  • Mass is the quantity of matter (scalar, same everywhere, kg).
  • Weight is the gravitational force on a body (vector, W = mg, changes with g, newton).
  • Apparent weight in a lift: moving up with acceleration a → W' = m(g + a); moving down → W' = m(g − a); free fall (a = g) → apparent weight = 0 (weightlessness).

5. Worked examples

Example 1. A force of 20 N acts on a 4 kg body. Find the acceleration. a = F/m = 20/4 = 5 m s⁻².

Example 2. A 2 kg ball moving at 3 m s⁻¹ is stopped in 0.2 s. Find the average force. Impulse = Δp = m(v − u) = 2(0 − 3) = −6 N s. F = Δp/t = −6/0.2 = −30 N (30 N opposing motion).

Example 3. A gun of mass 5 kg fires a bullet of 0.02 kg at 200 m s⁻¹. Find the recoil velocity of the gun. By conservation: 0 = m_b v_b + m_g v_g → v_g = −(0.02×200)/5 = −0.8 m s⁻¹.

6. Common mistakes

  • Mistake: Treating action and reaction as acting on the same body. Fix: They act on two different bodies, so they don't cancel.
  • Mistake: Confusing mass and weight. Fix: Mass is in kg (constant); weight is a force in N (= mg, varies with g).
  • Mistake: Forgetting units of impulse. Fix: Impulse is in N s, equal to change in momentum (kg m s⁻¹).

7. Practice (book-back style)

  1. State Newton's second law and derive F = ma.
  2. Define impulse and give its unit.
  3. State the law of conservation of linear momentum with one application.
  4. A 1000 kg car accelerates from rest to 20 m s⁻¹ in 10 s. Find the force.
  5. Differentiate mass and weight (any three points).

8. Answer key

  1. Rate of change of momentum ∝ force → F = Δp/Δt = m(v−u)/t = ma.
  2. Impulse = force × time = change in momentum; unit N s.
  3. Total momentum is conserved with no external force; e.g., recoil of a gun / rocket propulsion.
  4. a = (20−0)/10 = 2 m s⁻²; F = ma = 1000×2 = 2000 N.
  5. Mass: matter, scalar, kg, constant. Weight: force, vector, N, varies with g.

9. Quick revision

  • Physics Ch 1 · Newton's three laws, momentum, impulse, gravitation.
  • p = mv; F = ma = Δp/Δt; impulse J = Ft = Δp.
  • Conservation of momentum: m₁u₁+m₂u₂ = m₁v₁+m₂v₂.
  • F = Gm₁m₂/r²; g = GM/R²; W = mg.
  • Apparent weight changes in an accelerating lift; zero in free fall.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Linear momentum
p = m v
Vector; unit kg m s⁻¹.
Newton's second law
F = m a = Δp / Δt
Unit of force: newton (N).
Impulse
J = F × t = Δp
Large force for a short time; unit N s.
Conservation of momentum
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Holds when no external force acts.
Universal gravitation
F = G m₁m₂ / r²
G = 6.674×10⁻¹¹ N m² kg⁻².
Weight
W = m g
g = GM/R² ≈ 9.8 m s⁻².
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Treating action and reaction as acting on the same body
They act on two different bodies, so they do not cancel.
WATCH OUT
Confusing mass and weight
Mass is in kg (constant); weight is a force in N (= mg, varies with g).
WATCH OUT
Wrong unit for impulse
Impulse is in N s, equal to the change in momentum.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Concept
Define linear momentum and give its unit.
Show solution
Momentum p = mv, the product of mass and velocity; unit kg m s⁻¹.
Q2EASY· Numerical
A force of 20 N acts on a 4 kg body. Find its acceleration.
Show solution
a = F/m = 20/4 = 5 m s⁻².
Q3MEDIUM· Numerical
A 2 kg ball moving at 3 m s⁻¹ is stopped in 0.2 s. Find the average force.
Show solution
Δp = 2(0−3) = −6 N s; F = Δp/t = −6/0.2 = −30 N (30 N opposing motion).
Q4HARD· Conservation
A 5 kg gun fires a 0.02 kg bullet at 200 m s⁻¹. Find the recoil velocity of the gun.
Show solution
0 = m_b v_b + m_g v_g → v_g = −(0.02×200)/5 = −0.8 m s⁻¹.
Q5MEDIUM· Concept
Why is a person in a freely falling lift weightless?
Show solution
The lift accelerates downward with a = g, so apparent weight W' = m(g − g) = 0.
Q6MEDIUM· Reasoning
Differentiate mass and weight (two points).
Show solution
Mass: matter, scalar, kg, constant. Weight: gravitational force, vector, N, varies with g.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Physics Chapter 1 of Samacheer Kalvi Class 10 Science.
  • Newton's three laws; inertia and its types.
  • p = mv; F = ma = Δp/Δt; impulse J = Ft = Δp.
  • Conservation of momentum: m₁u₁+m₂u₂ = m₁v₁+m₂v₂.
  • F = Gm₁m₂/r²; g = GM/R²; W = mg.
  • Apparent weight varies in an accelerating lift; zero in free fall.

Tamil Nadu (TNBSE) marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 5-9 marks across MCQ, short and long answers in the SSLC paper

Question typeMarks eachTypical countWhat it tests
MCQ11-2Laws, units and definitions
Short Answer2-31-2Statements of laws and reasoning
Numerical / Long3-51Force, momentum and conservation problems
Prep strategy
  • Memorise the three laws and the key formulas
  • Practise force, momentum and impulse numericals
  • Master conservation-of-momentum sums (gun, rocket, collision)
  • Learn apparent-weight cases in a lift

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Rocket and jet propulsion

Conservation of momentum explains how rockets move by ejecting gas.

Safety in vehicles

Airbags and seat belts increase impact time, reducing force (impulse idea).

Sports

Follow-through in cricket/tennis increases contact time and momentum transfer.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Write the formula before substituting values in numericals
  2. Keep SI units and show each step for full marks
  3. State laws precisely in your own words
  4. Draw free-body sketches for force problems

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Derive the recoil velocity formula from conservation of momentum.
  • Show how Newton's second law reduces to F = ma for constant mass.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

TN SSLC Class 10 Public ExamHigh
Foundation / NTSE PhysicsMedium
School unit testsHigh

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

Momentum (mv) is the quantity of motion of a body; impulse (F×t) is the change produced in that momentum by a force acting for a time. Numerically, impulse equals the change in momentum.

Because they act on two different bodies. Only forces acting on the same body can be added or cancelled.
Verified by the tuition.in editorial team
Last reviewed on 2 June 2026. Written and reviewed by subject-matter experts — read about our process.
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