By the end of this chapter you'll be able to…

  • 1Plot points and identify quadrants
  • 2Apply the distance formula
  • 3Use the mid-point and section formulas
  • 4Find points of trisection
  • 5Calculate the centroid of a triangle
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Why this chapter matters
Coordinate Geometry links algebra with the plane. The distance, mid-point, section and centroid formulas give reliable, formula-driven marks in the TN Class 9 exam and prepare students for Class 10 coordinate geometry.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Coordinate Geometry — Class 9 Maths (Samacheer Kalvi)

TN State Board (Samacheer Kalvi) Class 9 Mathematics, Chapter 5. Locating points and measuring distances in the plane.


1. About this chapter

This chapter covers the Cartesian system, the distance formula, the mid-point and section formulas, points of trisection, and the centroid.

2. The Cartesian system

  • Two perpendicular axes (x and y) meet at the origin (0, 0), dividing the plane into four quadrants.
  • A point is written as an ordered pair (x, y).

3. Distance and mid-point

  • Distance formula: between A(x₁, y₁) and B(x₂, y₂): d = √[(x₂ − x₁)² + (y₂ − y₁)²].
  • Mid-point formula: mid-point of AB = ((x₁ + x₂)/2, (y₁ + y₂)/2).

4. Section formula and centroid

  • Section formula (point dividing AB in ratio m : n internally): ((m x₂ + n x₁)/(m + n), (m y₂ + n y₁)/(m + n)).
  • Points of trisection divide a segment into three equal parts (ratios 1 : 2 and 2 : 1).
  • Centroid of a triangle with vertices (x₁,y₁), (x₂,y₂), (x₃,y₃): ((x₁ + x₂ + x₃)/3, (y₁ + y₂ + y₃)/3).

5. Worked examples

Example 1. Find the distance between (1, 2) and (4, 6). d = √[(4 − 1)² + (6 − 2)²] = √(9 + 16) = √25 = 5.

Example 2. Find the mid-point of (2, 3) and (6, 7). = ((2 + 6)/2, (3 + 7)/2) = (4, 5).

Example 3. Find the centroid of the triangle with vertices (0,0), (6,0), (0,9). = ((0+6+0)/3, (0+0+9)/3) = (2, 3).

6. Common mistakes

  • Mistake: Forgetting to square inside the distance formula. Fix: d = √[(x₂ − x₁)² + (y₂ − y₁)²].
  • Mistake: Swapping m and n in the section formula. Fix: The ratio m : n multiplies the far then near coordinate carefully — write the formula before substituting.
  • Mistake: Dividing the centroid by 2 instead of 3. Fix: The centroid uses the average of three vertices (÷ 3).

7. Practice (book-back style)

  1. Write the distance formula.
  2. Find the distance between (0, 0) and (3, 4).
  3. Find the mid-point of (−2, 5) and (4, 1).
  4. Find the centroid of (1, 2), (3, 4), (5, 0).
  5. State the section formula.

8. Answer key

  1. d = √[(x₂ − x₁)² + (y₂ − y₁)²].
  2. √(9 + 16) = 5.
  3. ((−2 + 4)/2, (5 + 1)/2) = (1, 3).
  4. ((1+3+5)/3, (2+4+0)/3) = (3, 2).
  5. ((m x₂ + n x₁)/(m + n), (m y₂ + n y₁)/(m + n)).

9. Quick revision

  • Chapter 5 · distance, mid-point, section, centroid.
  • Distance d = √[(x₂−x₁)² + (y₂−y₁)²].
  • Mid-point = ((x₁+x₂)/2, (y₁+y₂)/2).
  • Section (m:n) = ((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)).
  • Centroid = ((x₁+x₂+x₃)/3, (y₁+y₂+y₃)/3).

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Distance formula
d = √[(x₂ − x₁)² + (y₂ − y₁)²]
Between two points.
Mid-point formula
((x₁ + x₂)/2, (y₁ + y₂)/2)
Average of the coordinates.
Section formula
((m x₂ + n x₁)/(m + n), (m y₂ + n y₁)/(m + n))
Internal division m : n.
Centroid
((x₁ + x₂ + x₃)/3, (y₁ + y₂ + y₃)/3)
Average of three vertices.
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Forgetting to square inside the distance formula
d = √[(x₂ − x₁)² + (y₂ − y₁)²].
WATCH OUT
Swapping m and n in the section formula
Write the formula before substituting and keep the ratio order.
WATCH OUT
Dividing the centroid by 2 instead of 3
The centroid averages three vertices (÷ 3).

NCERT exercises

Every NCERT exercise from this chapter — what it covers and how many questions to expect.

Multiple choice questions
Multiple choice questions
MCQs on quadrants and formulas.
5
Questions
Distance / mid-point
Distance / mid-point
Distance, mid-point and section problems.
6
Questions
Centroid / trisection
Centroid / trisection
Centroid and points-of-trisection problems.
4
Questions

Practice problems

Work through this chapter's problems as a readiness check — reveal each solution, mark yourself honestly, and get your gap report at the end.

Readiness check

Are you exam-ready for Coordinate Geometry?

6 problems from this chapter. Try each one, reveal the worked solution, mark yourself honestly — get your gap report at the end.

6 questions~4 min worth ~10 marks in Tamil Nadu (TNBSE) exams

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Chapter 5 of Samacheer Kalvi Class 9 Mathematics.
  • Distance d = √[(x₂−x₁)² + (y₂−y₁)²].
  • Mid-point = ((x₁+x₂)/2, (y₁+y₂)/2).
  • Section (m:n) = ((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)).
  • Centroid = ((x₁+x₂+x₃)/3, (y₁+y₂+y₃)/3).
  • Mid-point is the section formula with m = n = 1.

Tamil Nadu (TNBSE) marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 6-10 marks across MCQ, distance and centroid problems

Question typeMarks eachTypical countWhat it tests
MCQ11-2Quadrants and formulas
Short Answer2-31-2Distance, mid-point, section
Centroid / Trisection2-31Centroid and trisection points
Prep strategy
  • Memorise the four formulas
  • Practise distance and mid-point sums
  • Use the section formula carefully
  • Average three vertices for the centroid

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Mapping

Distances and mid-points locate places on coordinate maps.

Computer graphics

Points and centroids position and balance shapes.

Navigation

Coordinates describe routes and positions.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

1
Write the formula before substituting
2
Square the differences in the distance formula
3
Keep the ratio order in the section formula
4
Divide by 3 for the centroid

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

STRETCH
Show that the diagonals of a parallelogram bisect each other using mid-points.
STRETCH
Find a point dividing a segment externally in a given ratio.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

TN Class 9 Annual ExamHigh
Foundation / NTSE MathematicsMedium
School unit testsHigh

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

When the ratio is 1 : 1, the section formula reduces to the average of the coordinates, which is exactly the mid-point.

It is the point where the three medians meet — the triangle's balancing point — found by averaging the vertices' coordinates.
Verified by the tuition.in editorial team
Last reviewed on 3 June 2026. Written and reviewed by subject-matter experts — read about our process.
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