By the end of this chapter you'll be able to…

  • 1Compute overshoot and settling time of a second-order system
  • 2Find steady-state error from system type and apply the Routh criterion
  • 3Read gain and phase margins from Bode data
  • 4Compute rectifier average voltage and chopper output voltage
💡
Why this chapter matters in UPSC ESE (IES)
Both blocks reward a short list of formulas and procedures. Second-order response, the Routh array, rectifier averages and chopper gains solve most numerical questions.

Control Systems and Power Electronics — ESE Electrical

Weightage: Control systems and power electronics are two compact, high-scoring blocks in the Electrical papers. Both reward a clean toolkit: for control, the second-order formulas and Routh table, and for power electronics, the output-voltage relation of each converter.

1. Models and block diagrams

The transfer function is the ratio of the Laplace transform of the output to that of the input, with zero initial conditions. A closed loop with forward path and feedback has:

for negative feedback. Feedback reduces the sensitivity to parameter change, improves disturbance rejection and widens bandwidth, at the cost of gain and the risk of instability. Mason's gain formula finds the overall gain of a signal-flow graph from the forward paths, loops and non-touching loops.

2. Time response

A first-order system has a step response , reaching 63.2 percent at .

A standard second-order system is:

The damping ratio sets the shape: undamped at 0, underdamped for , critically damped at 1 and overdamped above 1. For the underdamped case:

QuantityFormula
Peak overshoot
Peak time
Settling time (2 percent)
Rise timeFalls as rises

Worked example. For and rad/s, and s.

Overshoot depends only on , so it is fixed by the pole angle, while settling time depends on the real part of the poles.

3. Steady-state error

For a unity-feedback system the type is the number of poles at the origin of . The error constants are , and .

TypeStepRampParabola
0
10
200

For (type 1), and the ramp error is . Raising the type improves accuracy, usually at the cost of stability.

4. Stability and the Routh criterion

A system is stable if all poles of the closed loop lie in the left half of the -plane. The Routh array counts right-half-plane roots by the sign changes in its first column. A necessary condition is that all coefficients of the characteristic polynomial are present and positive.

Worked example. For the first column is . The system is stable for , and at it is marginally stable with an oscillation at .

5. Root locus

The root locus plots the closed-loop poles as the gain varies from 0 to infinity. Rules:

  • It starts at open-loop poles () and ends at open-loop zeros or at infinity.
  • Real-axis segments lie to the left of an odd number of real poles and zeros.
  • The number of asymptotes is , with angles and a centroid .
  • Adding a pole pushes the locus toward the right, which reduces stability, while adding a zero pulls it to the left.

6. Frequency response: Bode and Nyquist

A Bode plot shows magnitude (in dB) and phase against log frequency. Each pole gives a slope of dB/decade after its corner frequency, and each zero dB/decade.

  • Gain margin: how much the gain can rise at the phase crossover frequency before instability.
  • Phase margin: how much extra phase lag is tolerated at the gain crossover frequency.

A stable system needs positive margins, and a phase margin of about 45 degrees is a common target. The Nyquist criterion says , with the closed-loop right-half-plane poles, the open-loop right-half-plane poles and the clockwise encirclements of .

Compensators. A lead network adds phase and speeds up response. A lag network improves steady-state accuracy and lowers bandwidth. A PID controller combines proportional, integral (removes steady-state error) and derivative (adds damping) action.

7. Power semiconductor devices

An SCR (thyristor) is a four-layer device that turns on by a gate pulse once forward biased and remains on until its current falls below the holding current. The latching current is the minimum anode current to keep it on after the gate pulse ends, and it is larger than the holding current. Turn-off needs commutation: natural (AC line), forced or load commutation.

Compare the controllable devices:

DeviceStrength
MOSFETHigh switching frequency, low voltage
IGBTMedium frequency, high voltage and current
GTOTurn-off by gate, high power

8. Controlled rectifiers

For a single-phase full-wave fully controlled bridge with continuous current, the mean output voltage is:

with firing angle . For a half-wave controlled rectifier with a resistive load, .

Worked example. At V and , V.

When the average voltage is negative, so with a source such as a DC motor the converter can invert, returning energy to the AC supply. A three-phase fully controlled bridge gives , with the peak line voltage. A freewheeling diode keeps load current flowing and raises the output of an inductive load circuit.

9. DC-DC converters and inverters

With duty ratio and input voltage :

ConverterOutput voltage
Buck (step-down)
Boost (step-up)
Buck-boost

So with and V a buck gives 40 V, and a boost with and V gives 100 V.

An inverter turns DC into AC. A single-phase full-bridge square-wave inverter gives an RMS output equal to the DC input, and PWM control shifts the harmonic content to higher frequencies so filtering is easier and the fundamental can be varied. A cycloconverter converts AC at one frequency to a lower frequency AC directly, and an AC voltage controller varies RMS voltage by phase angle. Snubbers protect devices against , and series inductors against .

Common traps

  • Reading settling time as dependent on only. It depends on .
  • Missing the sign-change count in the Routh array when a row of zeros arises.
  • Confusing holding and latching currents. Latching is larger.
  • Using the half-wave formula for a full bridge.
  • Boost converter output below input. It is always at least .

Memory aids

  • "Overshoot from zeta, settling from zeta omega": second-order response.
  • "Left half is stable": pole location.
  • "2Vm over pi cos alpha": full converter.

Summary

Control systems describe linear systems by transfer functions, time response, steady-state error and stability, checked by Routh, root locus, Bode and Nyquist methods. Compensators reshape the response.

Power electronics converts electrical energy using SCRs and controllable switches, in controlled rectifiers, choppers and inverters whose output voltages follow compact formulas.

Exam protocol

  • Identify the system type and order before choosing a formula.
  • Build the Routh array row by row.
  • Name the converter before quoting its output voltage.
  • Check the sign of the average voltage when exceeds 90 degrees.

Key formulas & results

Everything to memorise for the exam hall, in one card. Screenshot this for revision.

Peak overshoot
Depends only on the damping ratio.
Settling time (2 percent)
Set by the real part of the poles.
Full controlled bridge
Single phase, continuous conduction.
Boost converter
Buck is D V_s.
Closed-loop transfer function
Negative feedback.
⚠️

Traps UPSC ESE (IES) sets — and how to dodge them

These are the exact option-traps and misreads that cost marks under negative marking.

WATCH OUT
✗ Making settling time depend on the damping ratio alone.
✓ It depends on the product of damping ratio and natural frequency.
WATCH OUT
✗ Ignoring special cases in the Routh array.
✓ Handle a zero in the first column or a row of zeros with the standard rules.
WATCH OUT
✗ Confusing holding and latching current.
✓ Latching current is larger than holding current.
WATCH OUT
✗ Using the half-wave formula for a full bridge.
✓ Use 2Vm over pi times cos alpha for the full bridge.
WATCH OUT
✗ Expecting a boost converter to give less than its input.
✓ Output is at least the input.

Exam-pattern practice

PYQ-style questions with full solutions. Work through them as a readiness check — mark yourself honestly and get your gap report at the end.

Readiness check

Are you exam-ready for Control Systems and Power Electronics?

8 problems from this chapter. Try each one, reveal the worked solution, mark yourself honestly — get your gap report at the end.

8 questions~6 min

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • •Closed loop G over (1 + GH); feedback reduces sensitivity, adds bandwidth.
  • •Overshoot depends on zeta only; settling time is 4 over zeta omega n.
  • •Type counts poles at the origin; type 1: ramp error 1 over Kv.
  • •Routh: sign changes in the first column count right-half-plane roots.
  • •Root locus: asymptote angles 180(2k+1)/(P - Z) and centroid.
  • •Gain margin at phase crossover; phase margin at gain crossover.
  • •Full bridge 2Vm cos alpha over pi; buck DVs; boost Vs/(1 - D).

UPSC ESE (IES) question blueprint

How this topic is asked, tier by tier — so you can prep to the pattern.

Typical weightage: 40

Question styleMarks eachTypical countWhat it tests
Overshoot~2-4 marks in a typical paper
Chopper~2-4 marks in a typical paper
Routh~4-6 marks in a typical paper
Steady-state error~4-6 marks in a typical paper
Settling time~4-6 marks in a typical paper
Rectifier~6-8 marks in a typical paper
Boost~6-8 marks in a typical paper
SCR~2-4 marks in a typical paper
Prep strategy
  • System type and order
  • Routh row by row
  • Name the converter

Exam-hall strategy

Battle-tested tips from mentors and toppers for this topic under the sectional clock.

  1. Identify system type and order first.
  2. Build the Routh array row by row.
  3. Name the converter before quoting its formula.

Beyond the exam

Where this skill shows up in the job you're competing for — and in life.

Industrial control loops

PID loops hold temperature, speed and level using the stability tools described.

Drives and power supplies

Rectifiers, choppers and inverters run motor drives and regulated supplies.

Where else this topic is tested

Prepare once, score in every exam that asks it.

ESE Electrical Prelims Paper IIControl systems and power electronics
ESE Electrical Mains Paper IIControl and power electronics

Questions aspirants ask

Pulled from the Q&A community and mentor sessions.

Know the criterion Z = N + P and how gain and phase margins are read from a Bode plot.

When the firing angle exceeds 90 degrees and the DC side can supply energy, such as a motor in regeneration.
Header Logo