Coding–Decoding (New Pattern) — Practice

Question 1

'he is tall' = sa re na; 'she is short' = re pi tu. The code for 'is' is:
(a) sa  (b) re  (c) na  (d) pi

Accepted Answer

'is' is the common word; the shared code between {sa,re,na} and {re,pi,tu} is 're'.

Answer: (b) re.

Question 2

'bank gives loan' = pa ta ni; 'gives money fast' = ni ka la; 'loan for money' = ta ka za. The code for 'bank' is:
(a) pa  (b) ta  (c) ni  (d) ka

Accepted Answer

ni=gives (S1∩S2), ta=loan (S1∩S3), ka=money (S2∩S3). Sentence 1 leftover = pa ⇒ bank.

Answer: (a) pa.

Question 3

If DELHI is coded GHOKL, then MUMBAI is:
(a) PXPEDL  (b) PXPEDM  (c) OWOCDK  (d) PYPEDL

Accepted Answer

Shift +3 (D→G, E→H…). M→P, U→X, M→P, B→E, A→D, I→L.

Answer: (a) PXPEDL.

Question 4

If LAMP → 12,1,13,16, then WORD → ?
(a) 23,15,18,4  (b) 22,15,18,4  (c) 23,14,18,3  (d) 24,15,17,4

Accepted Answer

W=23 (Y25−2), O=15, R=18, D=4.

Answer: (a) 23,15,18,4.

Question 5

In a code where A→Z, B→Y, C→X …, the word CAB becomes:
(a) XZY  (b) XYZ  (c) YZX  (d) ZXY

Accepted Answer

Opposite = 27 − position: C(3)→X, A(1)→Z, B(2)→Y.

Answer: (a) XZY.

Question 6

'red car fast' = mo jo lo; 'car is red' = jo ti mo. Which code is still ambiguous after these two sentences?
(a) 'car' and 'red' (mo/jo)  (b) 'fast' (lo)  (c) 'is' (ti)  (d) none

Accepted Answer

Sentences 1 and 2 share TWO words (red, car), giving codes {mo,jo} for {red,car} without a unique split. 'fast'=lo and 'is'=ti are fixed by elimination. A third sentence is needed to separate mo/jo.

Answer: (a) 'car' and 'red' (mo/jo).

Practice — Coding–Decoding (New Pattern)

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