By the end of this chapter you'll be able to…

  • 1Distinguish an equation from an expression
  • 2Set up an equation from a word problem by assigning a variable
  • 3Solve simple equations using the balancing method and transposition
  • 4Apply equations to number, age, money, and geometry problems
  • 5Verify a solution by substituting it back into the original equation
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Why this chapter matters
Simple equations are the gateway to algebra. Every higher mathematics topic -- linear equations, quadratic equations, coordinate geometry -- builds on equation-solving skills. This chapter connects directly to Class 8 Linear Equations in One Variable and trains students to translate real-world word problems into solvable equations.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Simple Equations - Class 7 Mathematics (CBSE)

Based on the 2025-26 NCERT syllabus for Class 7 Mathematics. This chapter introduces the concept of algebraic equations -- setting them up from word problems and solving them systematically using balancing methods.


1. Why this chapter matters

Simple equations are the gateway to algebra. Every higher mathematics topic -- linear equations, quadratic equations, coordinate geometry -- builds on equation-solving skills. In CBSE exams, this chapter is worth 6-8 marks and connects directly to Class 8 Linear Equations in One Variable.

2. What is an equation?

An equation is a mathematical statement where two expressions are equal, connected by the equals sign (=).

An equation always has:

  • A left-hand side (LHS)
  • A right-hand side (RHS)
  • An equals sign between them
  • At least one variable (unknown quantity)

Example: 2x + 3 = 11

Equation vs expression

ExpressionEquation
3x + 53x + 5 = 14
No equals signHas an equals sign
Cannot be solvedCan be solved for the variable

3. Setting up equations from word problems

Translation table

Word/phraseMathematical symbol
is, are, equals=
more than, sum, added to+
less than, difference, subtracted from-
times, product of, multiplied byx
divided by, ratio/
a number, some numberx (or any variable)

Steps to set up an equation

  1. Read the problem carefully.
  2. Identify the unknown quantity and assign a variable.
  3. Translate the words into a mathematical equation.
  4. Solve the equation.
  5. Verify the solution.

4. Solving equations by balancing

The balance principle

Whatever operation you perform on one side of the equation, you must perform the same operation on the other side.

Solving steps

To isolate the variable:

  1. Add or subtract the same number on both sides.
  2. Multiply or divide both sides by the same non-zero number.
  3. Transpose terms (move terms from one side to the other, changing sign).

Transposition

Moving a term from one side to the other reverses its operation:

  • Addition becomes subtraction and vice versa.
  • Multiplication becomes division and vice versa.

5. Applications

Number problems

Example: A number increased by 12 is 25. Find the number. Equation: x + 12 = 25. Solution: x = 13.

Age problems

Example: Raj is 7 years older than Priya. Their total age is 33. Find their ages. Let Priya's age = x. Raj's age = x + 7. Equation: x + (x + 7) = 33. 2x + 7 = 33. 2x = 26. x = 13. Priya is 13, Raj is 20.

Geometry problems

Example: The perimeter of a rectangle is 40 cm. Its length is 5 cm more than its breadth. Find the dimensions. Let breadth = b cm. Length = b + 5 cm. Perimeter = 2(l + b) = 2(b + 5 + b) = 2(2b + 5) = 4b + 10 Equation: 4b + 10 = 40. 4b = 30. b = 7.5 cm. Length = 12.5 cm.

Money problems

Example: A total of Rs. 500 is divided between two friends such that one gets Rs. 80 more than the other. How much does each get? Let smaller share = x. Larger share = x + 80. Equation: x + (x + 80) = 500. 2x + 80 = 500. 2x = 420. x = 210. One gets Rs. 210, the other gets Rs. 290.

6. Worked examples

Example 1: Solve 3x - 7 = 14

Add 7 to both sides: 3x = 21. Divide by 3: x = 7. Verify: 3(7) - 7 = 21 - 7 = 14. Correct.

Example 2: Solve (y/4) + 3 = 5

Subtract 3 from both sides: y/4 = 2. Multiply by 4: y = 8. Verify: 8/4 + 3 = 2 + 3 = 5. Correct.

Example 3: Solve 2(x + 3) = 18

Divide both sides by 2: x + 3 = 9. Subtract 3: x = 6. Verify: 2(6 + 3) = 2 x 9 = 18. Correct.

Example 4: The sum of three consecutive numbers is 51. Find them.

Let numbers be x, x + 1, x + 2. Equation: x + (x + 1) + (x + 2) = 51. 3x + 3 = 51. 3x = 48. x = 16. Numbers: 16, 17, 18.

7. Common mistakes and how to fix them

MistakeFix
Not transposing the sign correctlyWhen moving a term, reverse its operation
Forgetting to do same operation on both sidesWhatever you do to LHS, do to RHS too
Mistaking expression for equationAn equation must have an equals sign
Wrong variable assignmentRead carefully what the question asks for
Not verifying the answerSubstitute solution back into original equation

8. CBSE exam focus

Question typeMarksFrequency
Solve simple equation2 marks1-2 questions
Set up equation from statement2 marks1 question
Word problem (age/number)3 marks1 question
Geometry application3 marksOccasional
Equation with brackets3 marks1 question

9. Self-test

  1. Solve: 5x - 3 = 22.
  2. Solve: (2y/3) + 1 = 7.
  3. Solve: 4(2x - 1) = 28.
  4. The sum of two numbers is 45. One number is 9 more than the other. Find the numbers.
  5. Rohan's father is 3 times as old as Rohan. The sum of their ages is 48. Find Rohan's age.
  6. The length of a rectangle is 4 cm more than its width. The perimeter is 48 cm. Find the length and width.

10. Answer key

  1. 5x = 25. x = 5.
  2. 2y/3 = 6. 2y = 18. y = 9.
  3. 2x - 1 = 7. 2x = 8. x = 4.
  4. Let numbers be x and x + 9. 2x + 9 = 45. 2x = 36. Numbers: 18 and 27.
  5. Let Rohan = x years. Father = 3x. 4x = 48. x = 12. Rohan is 12 years old.
  6. Let width = w. Length = w + 4. 2(w + w + 4) = 48. 4w + 8 = 48. 4w = 40. w = 10 cm, length = 14 cm.

11. Quick revision

  • An equation states that two expressions are equal.
  • To solve, isolate the variable using inverse operations.
  • Whatever you do to one side, do to the other.
  • Transposition changes the sign or operation.
  • Always verify by substituting the answer back.
  • Set up equations by carefully translating word statements.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Balance principle
Whatever operation is done on the LHS must be done on the RHS.
Adding, subtracting, multiplying, or dividing both sides by the same value keeps the equation balanced.
Transposition
Moving a term to the other side reverses its operation (+ becomes -, x becomes /).
x + 12 = 25 becomes x = 25 - 12 = 13.
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Not transposing the sign correctly
When moving a term across the equals sign, reverse its operation: addition becomes subtraction, multiplication becomes division.
WATCH OUT
Forgetting to perform the same operation on both sides
Whatever you do to the LHS, you must do to the RHS too -- the equation must stay balanced.
WATCH OUT
Mistaking an expression for an equation
An equation must have an equals sign; an expression (like 3x + 5) cannot be solved.
WATCH OUT
Not verifying the answer
Always substitute your solution back into the original equation to confirm it works.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Solve
Solve: 5x - 3 = 22.
Show solution
Add 3 to both sides: 5x = 25. Divide by 5: x = 5.
Q2MEDIUM· Solve
Solve: (2y/3) + 1 = 7.
Show solution
Subtract 1: 2y/3 = 6. Multiply by 3: 2y = 18. Divide by 2: y = 9.
Q3MEDIUM· Brackets
Solve: 4(2x - 1) = 28.
Show solution
Divide by 4: 2x - 1 = 7. Add 1: 2x = 8. Divide by 2: x = 4.
Q4MEDIUM· Age Problem
Rohan's father is 3 times as old as Rohan. The sum of their ages is 48. Find Rohan's age.
Show solution
Let Rohan = x. Father = 3x. x + 3x = 48 -> 4x = 48 -> x = 12. Rohan is 12 years old.
Q5HARD· Geometry
The length of a rectangle is 4 cm more than its width. The perimeter is 48 cm. Find the length and width.
Show solution
Let width = w. Length = w + 4. 2(w + w + 4) = 48 -> 4w + 8 = 48 -> 4w = 40 -> w = 10 cm, length = 14 cm.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • An equation states that two expressions are equal and has an equals sign.
  • To solve, isolate the variable using inverse operations.
  • Whatever you do to one side, do to the other.
  • Transposition changes the sign or operation of a moved term.
  • Always verify by substituting the answer back.
  • Set up equations by carefully translating word statements.

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 6-8 marks depending on school paper design

Question typeMarks eachTypical countWhat it tests
Solve simple equation21-2Balancing and transposition
Set up equation from statement21Translating words into algebra
Word problem31Age, number, money, or geometry application
Prep strategy
  • Practise translating word phrases into mathematical symbols
  • Always isolate the variable step by step
  • Verify every solution by substitution
  • Read carefully what the question asks before assigning the variable

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Budgeting and money sharing

Splitting an amount so one person gets a fixed sum more than another is solved with a simple equation.

Age and time puzzles

Finding ages given relationships and totals is classic equation-solving used in reasoning tests.

Geometry and measurement

Finding unknown dimensions from a known perimeter or area requires setting up and solving an equation.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Define the variable clearly before writing the equation
  2. Show every balancing or transposition step for partial marks
  3. Verify the answer by substitution
  4. State the final answer in words with units for word problems

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Solve problems involving two related unknowns by expressing both in terms of one variable.
  • Explore equations where the variable appears on both sides and learn to collect like terms.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 7 School ExamHigh
International Mathematics Olympiad (IMO) Level 1Medium
NTSE foundation (algebra)Low now, useful as foundation

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

An expression (like 3x + 5) is a phrase with no equals sign and cannot be solved. An equation (like 3x + 5 = 14) states that two expressions are equal and can be solved for the variable.

Transposition is moving a term from one side of the equation to the other while reversing its operation. For example, in x + 7 = 10, transposing the 7 gives x = 10 - 7 = 3.
Verified by the tuition.in editorial team
Last reviewed on 29 May 2026. Written and reviewed by subject-matter experts — read about our process.
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