By the end of this chapter you'll be able to…

  • 1Classify any sample of matter as element, compound, or mixture (homogeneous/heterogeneous)
  • 2Distinguish solutions, colloids and suspensions by particle size, Tyndall effect and filter-paper behaviour
  • 3Compute mass percentage and volume percentage of a solute in a given solution
  • 4Identify the correct separation technique for any given mixture
  • 5Explain the Tyndall effect with at least three everyday examples
  • 6Distinguish miscible vs immiscible liquids and choose the right separation method
  • 7Name the eight common physical separation techniques and the kind of mixture each is used for
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Why this chapter matters
This chapter is the conceptual gateway to all of chemistry. Once you can distinguish a compound from a mixture and a colloid from a solution, you can read any pharmaceutical label, food ingredients list or material data sheet with chemical understanding.

Is Matter Around Us Pure? — Class 9 (CBSE)

A scientist's "pure" is much stricter than a grocer's "pure." Pure milk on a packet means "no added water." Pure to a chemist means "made of only one kind of particle." This chapter teaches you to think like a chemist about every glass of water, every breath of air, and every spoonful of food.


1. The story — purity matters

In 1947 the Indian railway network was already vast, but mineral water was unknown. Travellers carried earthen pots ("surai") of water. By the 1980s, packaged "pure" water became a Rs. 50,000-crore industry in India. The word "pure" sells. But what does it really mean?

To a chemist, pure matter consists of only ONE kind of particle. Distilled water is pure (only H₂O molecules). The water in your bottle is NOT pure — it contains dissolved minerals, oxygen, sometimes chlorine. It's a mixture.

This chapter does three things:

  • Classifies all matter into pure substances vs mixtures (and further).
  • Teaches you to recognise solutions, suspensions and colloids by particle size and the Tyndall effect.
  • Gives you the standard methods to physically SEPARATE the components of a mixture.

2. The classification tree — memorise this picture

                    Matter
                      |
        +-------------+-------------+
        |                           |
   Pure substance              Mixture
        |                           |
   +----+----+              +-------+-------+
   |         |              |               |
 Element  Compound      Homogeneous   Heterogeneous
   |         |              |               |
   H, O    H₂O,         salt soln,    sand+water,
   Au, Cu   CO₂,         air,         oil+water,
            NaCl         alloys       chalk+water

Two-sentence summary:

  • Pure substances (elements & compounds) have a fixed composition and fixed properties.
  • Mixtures (homogeneous & heterogeneous) have variable composition and the properties of their constituents.

3. Pure substances — element vs compound

Element

  • Made of ONLY ONE type of atom. Cannot be broken down by ordinary chemical means.
  • Currently 118 known elements (94 natural, 24 synthetic).
  • Categories: Metals (iron, copper, gold), Non-metals (oxygen, carbon, sulphur), Metalloids (silicon, germanium — properties between metal and non-metal).

Compound

  • Two or more elements in a fixed ratio, chemically combined.
  • Properties are completely different from those of the constituent elements.
  • Example: water (H₂O) is liquid; hydrogen and oxygen alone are gases. Salt (NaCl) is edible; sodium is a violently reactive metal and chlorine is a poison gas. Chemical combination changes everything.
  • Constituents can be separated only by chemical methods (electrolysis, decomposition), not physical ones.

Element vs Compound — the 4-test memorisation table

QuestionElementCompound
How many types of atoms?OneTwo or more
Can be broken down chemically?NoYes
Fixed ratio?N/AYes
Properties vs constituents?Same as itselfDifferent from elements

4. Mixtures — homogeneous vs heterogeneous

Homogeneous mixture (= solution)

  • Uniform composition throughout. Cannot see boundaries between components.
  • One phase visible everywhere.
  • Examples: salt water, sugar water, air, brass (Cu + Zn), bronze, stainless steel.

Heterogeneous mixture

  • Non-uniform; you can see (sometimes only with a microscope) different regions.
  • Two or more visible phases.
  • Examples: sand + water, oil + water, chalk + water, granite, soil.

The line between homogeneous and heterogeneous isn't always crisp — it depends on the scale you look at. Colloids look homogeneous to the eye but are heterogeneous under a microscope (they're an in-between case, more in §6).


5. Solutions — homogeneous mixtures explored

A solution is a homogeneous mixture of two or more substances. The component present in larger amount is the solvent; the smaller one is the solute.

TypeSolventSoluteExample
Solid in liquidLiquidSolidSalt in water
Liquid in liquidLiquidLiquidVinegar (acetic acid in water)
Gas in liquidLiquidGasSoda water (CO₂ in water)
Solid in solid (alloy)SolidSolidBrass (Zn in Cu)
Gas in gasGasGasAir (O₂ in N₂)

Properties of a true solution

  1. Homogeneous — uniform.
  2. Particle size very small ().
  3. Particles do NOT settle when left undisturbed.
  4. Particles pass through filter paper — too small to be filtered.
  5. Light passes straight through — no scattering (no Tyndall effect).
  6. Stable — components don't separate over time.

Saturated and unsaturated solutions

  • Unsaturated: more solute can still dissolve at that temperature.
  • Saturated: cannot dissolve any more solute at that temperature.
  • Supersaturated: more solute dissolved than usual (achieved by heating then cooling carefully); unstable.

Concentration formulas — memorise both

Mass percentage (most common in CBSE):

Volume percentage (for liquid solutes):

Note: mass of solution = mass of solute + mass of solvent. Don't confuse with "mass of solvent" — common 1-mark trap.


6. Suspensions and colloids — the in-between cases

Suspension

  • A heterogeneous mixture where solute particles are big enough to be visible (or large enough to settle out).
  • Particle size .
  • Particles settle down when left.
  • Particles are retained by filter paper.
  • Example: chalk + water, muddy water, paints (before stirring).

Colloid

  • A heterogeneous mixture that LOOKS homogeneous to the naked eye.
  • Particle size between and .
  • Particles do NOT settle.
  • Particles pass through filter paper but are stopped by special ultrafilters.
  • Show the Tyndall effect: scatter light, making a visible beam.

Tyndall effect — the colloid signature

When a beam of light passes through:

  • A solution → light passes through invisibly.
  • A colloid → light is scattered by colloidal particles → the beam is visible.

Examples you've seen:

  • Sunbeam through a dusty room.
  • Sunlight through forest mist or fog.
  • Headlights cutting through mist on a foggy night.

Types of colloids (memorise this table — 2-mark question)

Dispersing mediumDispersed phaseTypeExample
GasLiquidAerosolFog, mist, clouds, deodorant spray
GasSolidAerosolSmoke, dust storm
LiquidGasFoamSoap foam, shaving cream, fire-extinguisher foam
LiquidLiquidEmulsionMilk, butter (in cream), face cream
LiquidSolidSolPaint, blood, ink, jellies (gels are similar)
SolidGasSolid foamSponge, bread, pumice stone
SolidLiquidGelJelly, butter, cheese
SolidSolidSolid solColoured gemstones, alloys

The three particle-size regimes — memorise

TypeParticle sizeTyndall?Settles?Filter paper?
Solution< 1 nmNoNoPasses
Colloid1 nm – 1 μmYESNoPasses (use ultrafilter)
Suspension> 1 μmYESYesRetained

7. Separation techniques — which method for which mixture?

CBSE tests this with great consistency. Match each method to the mixture type.

Filtration

For: insoluble solid + liquid (suspension). Examples: sand from water, tea leaves from tea.

Evaporation

For: soluble solid from liquid (solution). Examples: salt from sea water.

Centrifugation

For: small particles that won't filter (colloids, blood). Spin fast → heavier particles move outward → light supernatant on top. Example: separating cream from milk, separating plasma from blood cells.

Sublimation

For: separating a subliming solid from a non-subliming solid. Example: ammonium chloride mixed with sand.

Distillation

For: separating two miscible liquids with large boiling-point difference (> 25 °C). The component with the lower boiling point evaporates first, condenses in the condenser, collected as distillate. Example: water and acetone, water and alcohol.

Fractional distillation

For: two miscible liquids with small boiling-point difference (< 25 °C). Uses a fractionating column packed with glass beads. Example: petrol and diesel from crude oil, separating gases of liquefied air (O₂, N₂, Ar all have similar BPs).

Chromatography

For: separating dyes, pigments — typically dissolved solid solutes. Different components travel different distances on the chromatography paper. Example: separating the dyes in black ink, plant pigments.

Separating funnel

For: two immiscible liquids (won't mix — form layers). Example: oil and water, kerosene and water.

Crystallisation

For: getting pure solid crystals from a solution (better than evaporation for impurities-laden solutions). Example: pure copper sulphate crystals from impure sample.


8. Closing thought

Almost nothing in your life is pure — and that's a good thing. Pure water has no minerals; you'd get deficiencies. Pure oxygen is dangerous; humans live in 21% oxygen with 78% nitrogen. Bronze, an alloy of copper and tin, is stronger than either pure metal. Steel, an iron-carbon mixture, built the modern world.

Mixtures are everywhere because they're useful. What chemistry gives you is the language to describe them precisely (solution vs colloid vs suspension), the tools to measure them (Tyndall effect, mass %), and the methods to separate them (eight techniques you just learned). Walk into any chemical industry, soap factory, oil refinery or pharma plant and you'll see these eight separation techniques scaled up to industrial size.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Mass percentage
% by mass = (mass of solute / mass of solution) × 100
Solution = solute + solvent. Common 1- and 2-mark numerical.
Volume percentage
% by volume = (volume of solute / volume of solution) × 100
Used for liquid-in-liquid solutions like alcohol-water.
Mass of solution
Mass of solution = mass of solute + mass of solvent
The most-missed step in CBSE numericals.
Concentration ranges (size)
Solution < 1 nm · Colloid 1 nm–1 μm · Suspension > 1 μm
Memorise — directly tested.
⚠️

Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Treating air as a pure substance
Air is a HOMOGENEOUS mixture of N₂, O₂, Ar, CO₂ and water vapour. The 'one phase' look fools many — but composition isn't fixed.
WATCH OUT
Calling milk a solution
Milk is a COLLOID (emulsion of fat in water). It scatters light (Tyndall effect) and shows particles under a microscope.
WATCH OUT
Using mass of solvent instead of mass of solution in mass %
Always: mass of SOLUTION (solute + solvent) goes in the denominator.
WATCH OUT
Saying 'a compound's properties are similar to its elements'
A compound's properties are usually COMPLETELY different. Sodium + chlorine (reactive metal + poison gas) → NaCl (table salt).
WATCH OUT
Choosing distillation for water + sand
Use filtration. Distillation only for two liquids; sand is a SOLID.
WATCH OUT
Choosing distillation for petrol + diesel
Use FRACTIONAL distillation — their boiling points are too close (< 25 °C apart) for simple distillation.
WATCH OUT
Saying colloids settle down
Colloids do NOT settle (suspensions do). That's how Tyndall + non-settling separates colloids from suspensions.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Classify
Classify each as an element, compound or mixture: (a) Sodium chloride, (b) Brass, (c) Hydrogen, (d) Sugar solution.
Show solution
Step 1 — Apply the definitions. Element: one type of atom; Compound: two+ elements in fixed ratio chemically bonded; Mixture: physical combination, variable composition. Step 2 — Classify each. (a) NaCl: two elements (Na, Cl) chemically combined → COMPOUND. (b) Brass: Cu + Zn alloy, variable composition → HOMOGENEOUS MIXTURE. (c) H₂: one type of atom → ELEMENT. (d) Sugar dissolved in water: variable composition → HOMOGENEOUS MIXTURE. ✦ Answer: (a) compound, (b) mixture, (c) element, (d) mixture.
Q2EASY· Solution
In 50 g of a salt solution containing 5 g of salt, identify the solute, solvent and the mass of solvent.
Show solution
Step 1 — Larger component = solvent; smaller = solute. Salt: 5 g (solute). Solvent: water. Step 2 — Mass of solvent = mass of solution − mass of solute. = 50 − 5 = 45 g. ✦ Answer: Solute = salt (5 g). Solvent = water (45 g). Mass of solvent = 45 g.
Q3EASY· Tyndall
Why is the Tyndall effect seen in fog but not in salt solution?
Show solution
Step 1 — Tyndall effect = light scattering by particles. Step 2 — Particle size comparison. Fog: colloid (water droplets, 1 nm–1 μm) → big enough to scatter light → beam is visible. Salt solution: true solution (particles < 1 nm) → too small to scatter visible light → beam invisible. ✦ Answer: Fog is a colloid with particles large enough to scatter light; salt solution has particles too small (true solution) to scatter visible light.
Q4EASY· Property
Name the property that distinguishes a suspension from a colloid.
Show solution
Step 1 — Compare suspension and colloid. Both are heterogeneous mixtures, but suspension's particles are larger. Step 2 — Identify the giveaway property. Suspension particles SETTLE when undisturbed; colloid particles do NOT settle. Additionally, suspension particles are RETAINED by filter paper; colloid particles PASS through ordinary filter paper. ✦ Answer: Suspension particles settle (and are filtered out by ordinary filter paper); colloid particles do not settle (and pass through filter paper). Either property is acceptable for 1 mark.
Q5EASY· Methods
Name the separation technique you would use to separate: (a) cream from milk, (b) iron filings from sand, (c) salt from sea water, (d) the dyes in a black-ink sample.
Show solution
Step 1 — Identify each mixture type and pick the method. (a) Cream from milk: colloid, small particles → CENTRIFUGATION. (b) Iron filings from sand: magnetic + non-magnetic → MAGNETIC SEPARATION. (c) Salt from sea water: solid dissolved in liquid → EVAPORATION. (d) Dyes in ink: pigments dissolved in water/alcohol → CHROMATOGRAPHY. ✦ Answer: (a) Centrifugation, (b) Magnetic separation, (c) Evaporation, (d) Chromatography.
Q6MEDIUM· Mass percent
A solution contains 40 g of sugar dissolved in 360 g of water. Calculate the mass percentage of the solution.
Show solution
Step 1 — Compute mass of solution. Mass of solution = mass of solute + mass of solvent = 40 + 360 = 400 g. Step 2 — Apply the formula. Mass % = (mass of solute / mass of solution) × 100 = (40 / 400) × 100 = 10 %. ✦ Answer: 10 %. Trap to avoid: NEVER use 360 g (mass of solvent) in the denominator. Always use 400 g (mass of solution).
Q7MEDIUM· Reverse calc
You're told a sugar solution is 15% sugar by mass and you need 60 g of sugar. How much water should you add?
Show solution
Step 1 — Let the total mass of solution be M grams. Mass % = (60 / M) × 100 = 15. Step 2 — Solve for M. 60 × 100 = 15 × M M = 6000 / 15 = 400 g. Step 3 — Mass of water. Water = M − sugar = 400 − 60 = 340 g. ✦ Answer: Add 340 g of water (the total solution becomes 400 g, of which 60 g is sugar = 15 %). Verification: 60/400 = 0.15 = 15 %. ✓
Q8MEDIUM· Classification
Classify each as solution, colloid or suspension AND justify with one observation: (a) Soap-water lather, (b) Sand stirred in water, (c) Sugar in water.
Show solution
Step 1 — Apply the size + behaviour tests. (a) Soap lather: small air bubbles in water; particles ~ 1 nm–1 μm; doesn't settle; scatters light → COLLOID (foam). Justification: Tyndall effect visible if you shine a torch through it; particles don't settle but lather isn't transparent. (b) Sand in water: visibly heterogeneous; particles > 1 μm; settles down within seconds; filter paper retains it → SUSPENSION. Justification: It settles on standing — the test for a suspension. (c) Sugar in water: clear, uniform; particles < 1 nm; doesn't settle; passes filter paper; no Tyndall effect → TRUE SOLUTION. Justification: Beam of light passes through without being visible. ✦ Answer: (a) Colloid, (b) Suspension, (c) Solution. Justifications as above.
Q9MEDIUM· Tyndall reason
Why is the Tyndall effect more visible through a forest canopy in the early morning than at noon? Justify with two reasons.
Show solution
Step 1 — Recall: Tyndall effect requires (i) colloidal-sized particles in the air, and (ii) a beam of light (so scattering is visible against a darker background). Step 2 — Conditions in a forest at different times. Morning: cool & humid → many water-droplet aerosols (mist, fog) — abundant colloidal particles. Sun is low, light enters at an angle, the scene is dark below the canopy → bright beams stand out clearly. Noon: warmer + drier → fewer aerosols; sun overhead, ambient light is bright → contrast is lost, beams are not visible against the bright background. ✦ Answer: (i) Morning air has more colloidal particles (mist, water droplets) → more scattering. (ii) Slanting morning sunlight cuts through a darker forest interior, making the scattered beam visible by contrast; midday's overhead bright light washes the beam out.
Q10MEDIUM· Method choice
Two miscible liquids A and B have boiling points 56 °C and 78 °C respectively. Which separation technique would you choose, and why?
Show solution
Step 1 — Check boiling-point difference. 78 − 56 = 22 °C. This is LESS than 25 °C. Step 2 — Rule. • Difference > 25 °C → simple distillation works. • Difference < 25 °C → use FRACTIONAL DISTILLATION (column with glass beads gives many tiny distillation cycles). Step 3 — Apply. Since the difference is 22 °C (< 25 °C), use fractional distillation. ✦ Answer: Use fractional distillation, because the boiling-point difference (22 °C) is too small for simple distillation to separate them effectively. The packed column provides repeated cycles of evaporation-condensation, achieving sharper separation.
Q11MEDIUM· Distillation
Why is fractional distillation, not simple distillation, used to separate gases of liquefied air?
Show solution
Step 1 — Recall the components of air after liquefaction. Nitrogen (BP −196 °C), Oxygen (BP −183 °C), Argon (BP −186 °C). Step 2 — Compare boiling-point differences. N₂ vs O₂: 13 °C apart. O₂ vs Ar: 3 °C apart. All < 25 °C. Step 3 — Apply the rule. Such small differences are impossible to separate by simple distillation (which gives only one evaporation-condensation cycle). A fractionating column allows many repeated cycles, ultimately separating each gas. ✦ Answer: Because the boiling-point differences of the air-gases (N₂, O₂, Ar) are all less than 25 °C — much too close for simple distillation. Fractional distillation gives the multiple equilibrium stages needed for sharp separation.
Q12HARD· Compound vs mix
Iron and sulphur are mixed in a 7:4 mass ratio and (a) stirred together, (b) heated strongly. Compare the products with respect to colour, magnetism and the effect of dilute H₂SO₄.
Show solution
Step 1 — Identify what happens in each case. (a) Stirring alone produces a MIXTURE of iron + sulphur powder (no chemical change). (b) Strong heating triggers a chemical reaction: Fe + S → FeS (iron sulphide, a COMPOUND). Step 2 — Compare on three properties. (i) Colour: Mixture: yellow sulphur visible mixed with grey iron filings — heterogeneous appearance. Compound (FeS): uniform black mass. (ii) Magnetism: Mixture: iron filings still attract a magnet — separable physically. Compound: NOT magnetic; iron is chemically combined and has lost its individual magnetic property. (iii) Reaction with dilute H₂SO₄: Mixture: produces odourless H₂ gas (from the iron) + leaves unreacted sulphur. Compound: produces H₂S gas (rotten-egg smell) — a clearly different chemical behaviour. Step 3 — Conclusion. Stirring keeps the elements' individual properties → mixture. Heating combines them at the atomic level → compound with brand-new properties. ✦ Answer: (a) Mixture: yellow + grey, magnetic, odourless gas with H₂SO₄. (b) Compound (FeS): uniformly black, non-magnetic, gives smelly H₂S gas with H₂SO₄. This is the classic experiment proving that 'compound ≠ mixture of constituent elements'.
Q13HARD· Process design
You're given a mixture of common salt (NaCl), ammonium chloride (NH₄Cl) and sand. Design a stepwise process to get all three components pure.
Show solution
Step 1 — Identify each component's distinguishing property. • Ammonium chloride: SUBLIMES on heating (solid → gas, no liquid). • Salt (NaCl): SOLUBLE in water, doesn't sublime. • Sand: INSOLUBLE in water, doesn't sublime. Step 2 — Design the sequence. Step (a) Sublimation: heat the dry mixture in a covered china dish. NH₄Cl sublimes and re-deposits on a cool inverted funnel above → recover NH₄Cl. Step (b) Add water to the residue (salt + sand). Salt dissolves; sand doesn't. Step (c) Filter through filter paper. • Filtrate: salt solution. • Residue: sand. Wash, dry → recover SAND. Step (d) Evaporate the filtrate to dryness OR crystallise to recover NaCl. Step 3 — Recap. Sublimation → Dissolution → Filtration → Evaporation. Four physical methods, three pure components recovered. ✦ Answer: Sublimation removes NH₄Cl first. Dissolution and filtration separate sand (residue) from salt (in solution). Evaporation/crystallisation recovers the salt. All three are recovered as pure substances.
Q14HARD· Concentration
300 g of a sugar solution at 60 °C contains 60 g of sugar. (a) Find its mass percentage. (b) If cooled to room temperature 18 g of sugar separates out (crystallises), find the mass percentage of the saturated solution at room temperature.
Show solution
Step 1 (a) — Mass % at 60 °C. Mass % = (60 / 300) × 100 = 20 %. Step 2 (b) — After cooling, 18 g of sugar separates as solid. Sugar still dissolved = 60 − 18 = 42 g. Mass of saturated solution = original mass − separated solid = 300 − 18 = 282 g. Step 3 — Mass % of saturated solution. = (42 / 282) × 100 ≈ 14.89 % (≈ 14.9 %). ✦ Answer: (a) 20 %, (b) ≈ 14.9 %. Insight: solubility decreases with temperature for most solid solutes, so cooling forces some out as crystals — the basis of recrystallisation purification.
Q15HARD· Industrial
In a petroleum refinery, why is crude oil fractionally distilled in a tall column rather than batch-distilled, and what does the column's height correspond to physically?
Show solution
Step 1 — Recall what's in crude oil. A complex mixture of many hydrocarbons with boiling points ranging from < 40 °C (petrol, gasoline) to > 350 °C (lubricants, asphalt). Many fractions have BPs within a few °C of each other. Step 2 — Why fractional, not batch. Each plate/tray in the column is effectively one equilibrium stage. The taller the column, the more stages → the finer the separation. Batch distillation gives only ONE stage, which is hopeless for closely-boiling hydrocarbons. Step 3 — What the height physically represents. As vapour rises, it cools. Hotter (heavier) fractions condense lower in the column. Lighter (lower BP) fractions condense higher up. Each tray collects a different 'fraction': • Bottom: bitumen, lubricating oil. • Middle: diesel, kerosene. • Top: petrol, LPG, refinery gases. Column height ↔ number of equilibrium stages ↔ sharpness of separation. ✦ Answer: Fractional distillation in a tall column provides many equilibrium stages (each tray = one cycle of evaporation + condensation), which is essential when boiling-point differences are small. Height ↔ stages: the taller the column, the finer the separation between fractions.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Pure substance = single kind of particle. Two types: element (one atom kind), compound (two+ in fixed ratio chemically bonded).
  • Mixture = variable composition. Two types: homogeneous (solutions, alloys) and heterogeneous (sand+water, oil+water, colloids, suspensions).
  • Solution: particles < 1 nm, no Tyndall, passes filter, doesn't settle.
  • Colloid: 1 nm–1 μm, shows Tyndall, passes filter, doesn't settle.
  • Suspension: > 1 μm, shows Tyndall, retained by filter, SETTLES on standing.
  • Mass % = (solute / solution) × 100. Solution = solute + solvent.
  • Tyndall effect = colloidal particles scattering light, making beam visible.
  • Separation methods: filtration (insoluble solid), evaporation (soluble solid), distillation (>25 °C BP diff), fractional (<25 °C), chromatography (dyes), separating funnel (immiscible liquids), centrifugation (colloid), sublimation (NH₄Cl from salt).
  • Fe + S stirred = mixture (magnetic, gives H₂); heated = FeS compound (non-magnetic, gives H₂S).

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

A mixture. Its components (N₂ ≈ 78 %, O₂ ≈ 21 %, Ar ≈ 0.9 %, CO₂ ≈ 0.04 %, plus water vapour) are not in fixed ratios and can be separated by physical means (cooling to liquid air, then fractional distillation).

Under a microscope you can see tiny fat globules dispersed in water — particles roughly 1 μm in size. Light passes through milk shows the Tyndall effect. Both criteria mark it as a colloid (specifically an emulsion).

Yes. Coloured gemstones (e.g., ruby = chromium dispersed in aluminium oxide) and some alloys are solid sols. The dispersed phase is finely distributed solid particles within a solid medium.

Sucrose (table sugar) is a compound (C₁₂H₂₂O₁₁) — fixed composition, can be decomposed chemically. Sugar dissolved in water is then a mixture (solution).

Brass is a solid solution. The zinc atoms slip into the copper lattice, disrupting the lattice slightly and producing new mechanical properties (harder, more corrosion-resistant). Even though it's a mixture, the atomic-level mixing changes how stress propagates through the metal.

No — by definition a solution has a solvent (the bulk) and a solute (dissolved in it). A material that's purely one substance is a pure substance, not a solution.
Verified by the tuition.in editorial team
Last reviewed on 18 May 2026. Written and reviewed by subject-matter experts — read about our process.
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